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adoni [48]
3 years ago
14

The 3670-lb car is traveling at 25 mi/hr when the driver applies the brakes, and the car continues to move along the circular pa

th. What is the maximum deceleration possible (at is negative if the speed is decreasing) if the tires are limited to a total horizontal friction force of 1930 lb
Physics
1 answer:
Monica [59]3 years ago
5 0

Answer:

  a_t = -14.37407175

Explanation:

I was unable to submit this answer after typing it, so i create a document file that clearly shows and depicts all explanations for the question. OR

You can check the three picture slides i attached as well for the explanation.

The attached file for the document and the picture can be found below.

Download docx
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> docx </span>
690240b35d7a8d28bfac88e03c23c95f.jpg
aab93cf3a7fccfd1e19a9706649af537.jpg
19421a98c2386d4e89fa09891eca0b7f.jpg
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5. Graph A below plots a race car's speed for 5 seconds. The car's rate of acceleration is 6 m/s^2
Georgia [21]

Answer:

The answer is below

Explanation:

We are to check if the statement is true of false. If it is false, we correct the statement.

Solution:

Acceleration is the time rate of change of velocity. It is the ratio of the change in velocity to the change in time. The acceleration can be gotten from a velocity time graph by finding the slope of the graph.

The x coordinate represent the time and the y coordinate velocity.

5) Graph A passes through the point (0, 0) and (4, 24). Therefore the acceleration (slope) is:

Acceleration = \frac{24-0}{4-0}=6\ m/s^2

This is correct.

6) Graph B is a straight line of 12 m/s. It passes through (0, 12) and (4, 12). Hence:

Acceleration = \frac{12-12}{4-0}=0\ m/s^2

This is false.

Therefore the acceleration of graph B is 0 m/s².

8 0
3 years ago
If the archerfish spits its water 30 degrees from the horizontal aiming at an insect 1.2 m above the surface of the water, how f
Burka [1]

Answer:

The speed is  v =  9.8 \ m/s

Explanation:

From the question w are told that

    The angle  made is \theta  =  30^o

     The distance  above the surface of the water is  h_{max} = 1.2 \ m

     The  value of  g = 10 \  m/s^2

   

The maximum height attained by the fish is mathematically evaluate as

       h_{max} =  \frac{v^2 sin ^2 \theta }{2g }

Making v which is the speed of the fish the subject of the formula

      v =  \sqrt{ \frac{2gh_{max}}{ sin^2 \theta } }

  substituting values

     v =  \sqrt{ \frac{2*10 *1.2 }{ [sin (30)]^2  } }

     v =  9.8 \ m/s

3 0
3 years ago
Which of the following is an example of newton second law of motion?
zaharov [31]

Answer: Its answer C: A wheelbarrow is more difficult to move as More objects are placed inside.

Explanation: The greater the mass of the object the more force is needed to make it move.

Hope this helps!! :)

4 0
4 years ago
a brick is suspended above the ground at a height of 6.6 m. it has a mass of 5.3 kg. what is the potential energy of the brick
Svetradugi [14.3K]
The formula for potential energy is
E(p) = mgh

(Mass x gravity x height)

Therefore energy = (5.3)(9.8)(6.6)
= 342.8 J

How did I get 9.8?
9.8 is the constant for gravity
8 0
4 years ago
Name three bright Saturn ring features, and explain why they are so bright.
Leviafan [203]

The F Ring, the Cassini Division, and the C Ring are bright ring features. They are bright due to the low concentration of materials within them, which allows sunlight to shine through.


6 0
3 years ago
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