Answer:
Part A
The distance travel by the rock is approximately 132.496 m
Part B
The speed when the rock hits the ground is approximately 50.96 m/s
Explanation:
Part A
The question is focused on the kinetics equation of a free falling object
The given parameter is the time it takes the rock to hit the ground, t = 5.2 s
For an object in free fall, we have;
h = 1/2·g·t²
Where;
h = The height from which the object is dropped
g = The acceleration due to gravity ≈ 9.8 m/s²
t = The time taken to travel the distance, h = 5.2 s
∴ h = 1/2 × 9.8 m/s² × (5.2 s)² ≈ 132.496 m
The distance travel by the rock, h ≈ 132.496 m
Part B
The speed, 'v', when the rock hits the ground, is given by the following kinematic equation,
v = g·t
∴ v = 9.8 m/s² × 5.2 s = 50.96 m/s
The speed when the rock hits the ground, v ≈ 50.96 m/s.
