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Phoenix [80]
3 years ago
12

A skateboarder rolls off a ledge that is 1.12 m high, and lands 1.48 m from the base of the edge. How much time was he in the ai

r?
Physics
1 answer:
nignag [31]3 years ago
3 0

The rider's horizontal motion, and how much ground he covers before he hits it, have nothing to do with how long he takes to hit the ground.  The problem is simply:  "How long does it take an object to fall 1.12 m from rest ?"

This seems like a good time to use this formula:

Distance fallen from rest = (1/2) (acceleration) (time)²

The problem doesn't tell us what planet the skateboarder is exercising  on. I'm going to assume it's on Earth, where the acceleration of gravity is 9.8 m/s².  And now, here's the solution to the problem I just invented:

1.12 m = (1/2) (9.8 m/s²) (time)²

Time²  = (1.12 m) / (9.8 m/s²)

Time²  = 0.1143 sec²

Time = √(0.1143 sec² )

<em>Time = 0.34 second</em>

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5 0
3 years ago
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an object has a momentum of 250 kg m/s what would be the momentum of an object that has half of the mass and going at the same v
Romashka-Z-Leto [24]

The momentum of the second object is 125 kg m/s

Explanation:

The momentum of an object is given by

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For the object in this problem,

p = 250 kg m/s

And its mass is m and its velocity is v.

The second object has a mass of m' = \frac{m}{2} and same velocity v, so its momentum is

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So, the second object has a momentum that is half of the momentum of the first object, therefore it is:

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Learn more about momentum:

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<u>Answer</u>

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longitudinal wave is a wave whose particles vibration is in the direction of wave travel.

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