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Firlakuza [10]
3 years ago
5

The color of an object that the human eye senses depends on the color of light that shines on the object and the color of light

that is reflected or absorbed by the object. If white light shines on an object and the object appears blue, this means that
A. the object absorbs all light that strikes it.
B. the object reflects blue light more than it does any other color.
C. the object reflects all light that strikes it.
D. the object absorbs blue light more than it does any other color.
Physics
2 answers:
klasskru [66]3 years ago
5 0

Answer: B

Explanation:

eduard3 years ago
4 0

Answer:

B. the object reflects blue light more than it does any other color.

Explanation:

The color of an object as we see it corresponds to the wavelength of the light that the object reflects.

Let's consider an object on which white light is shone, as in this problem. If the object absorbs all the possible wavelengths of visible light, the object will not reflect any colour, so it will appear black. However, if the object reflects at least one color, the light of that color (reflected by the object) will reach us, so we will see the object in that color.

Therefore, in this problem, the object appears blue because it reflects blue light more than the other colors.

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A particle with charge 3.01 µC on the negative x axis and a second particle with charge 6.02 µC on the positive x axis are each
ra1l [238]

Answer:

The third particle should be at 0.0743 m from the origin on the negative x-axis.

Explanation:

Let's assume that the third charge is on the negative x-axis. So we have:

E_{1}+E_{3}-E_{2}=0

We know that the electric field is:

E=k\frac{q}{r^{2}}

Where:

  • k is the Coulomb constant
  • q is the charge
  • r is the distance from the charge to the point

So, we have:

k\frac{q_{1}}{r_{1}^{2}}+k\frac{q_{3}}{r_{3}^{2}}-k\frac{q_{2}}{r_{2}^{2}}=0

Let's solve it for r(3).

\frac{3.01}{0.0429^{2}}+\frac{9.03}{r_{3}^{2}}-\frac{6.02}{0.0429^{2}}=0

r_{3}=0.0743\:  

Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.

I hope it helps you!

 

3 0
3 years ago
The gravitational force between two objects (mass1 = 10kg, mass2 = 6kg) is measured when the objects are 12 centimeters apart. I
Yanka [14]
Since the new distance is 3 times the old distance,
the new force is (1/3²) = 1/9th of the old force.

That's kind-of Choice-D, but I really don't like the way choice-D is worded.
"9 times smaller" is really pretty meaningless.  
8 0
3 years ago
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