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Firlakuza [10]
3 years ago
5

The color of an object that the human eye senses depends on the color of light that shines on the object and the color of light

that is reflected or absorbed by the object. If white light shines on an object and the object appears blue, this means that
A. the object absorbs all light that strikes it.
B. the object reflects blue light more than it does any other color.
C. the object reflects all light that strikes it.
D. the object absorbs blue light more than it does any other color.
Physics
2 answers:
klasskru [66]3 years ago
5 0

Answer: B

Explanation:

eduard3 years ago
4 0

Answer:

B. the object reflects blue light more than it does any other color.

Explanation:

The color of an object as we see it corresponds to the wavelength of the light that the object reflects.

Let's consider an object on which white light is shone, as in this problem. If the object absorbs all the possible wavelengths of visible light, the object will not reflect any colour, so it will appear black. However, if the object reflects at least one color, the light of that color (reflected by the object) will reach us, so we will see the object in that color.

Therefore, in this problem, the object appears blue because it reflects blue light more than the other colors.

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Answer:

Do find the answer in the attachment herein.

Explanation:

From the attached diagram:

I. Activation energy = Activated complex - ∆H(reactants)

Activation energy = 162-140 = 22Kj.

II. ∆H(reaction) = ∆H(products) - ∆H(reactants)

∆H(reaction) = 37 - 140 = -103Kj.

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si se deja caer un carrito desde el punto mas alto de ua psta de coches cuya altura es de 1.4m cual es la velocidad maxima que p
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Answer:

v = 5.24[m/s]

Explanation:

Este problema se puede resolver por medio del principio de la conservación de la energía, donde la energía potencial es igual a la energía cinética. Es decir a medida que el carrito desciende su energía potencial disminuye, pero su energía cinética aumenta.

E_{kin}=E_{pot}

Donde:

E_{kin}=\frac{1}{2} *m*v^{2} \\\\E_{pot}=m*g*h

Ahora reemplazando:

\frac{1}{2} *m*v^{2}=m*g*h\\\\0.5*v^{2}=9.81*1.4\\v=\sqrt{\frac{9.81*1.4}{0.5} }   \\\\v=5.24[m/s]

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