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Firlakuza [10]
3 years ago
5

The color of an object that the human eye senses depends on the color of light that shines on the object and the color of light

that is reflected or absorbed by the object. If white light shines on an object and the object appears blue, this means that
A. the object absorbs all light that strikes it.
B. the object reflects blue light more than it does any other color.
C. the object reflects all light that strikes it.
D. the object absorbs blue light more than it does any other color.
Physics
2 answers:
klasskru [66]3 years ago
5 0

Answer: B

Explanation:

eduard3 years ago
4 0

Answer:

B. the object reflects blue light more than it does any other color.

Explanation:

The color of an object as we see it corresponds to the wavelength of the light that the object reflects.

Let's consider an object on which white light is shone, as in this problem. If the object absorbs all the possible wavelengths of visible light, the object will not reflect any colour, so it will appear black. However, if the object reflects at least one color, the light of that color (reflected by the object) will reach us, so we will see the object in that color.

Therefore, in this problem, the object appears blue because it reflects blue light more than the other colors.

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The law of multiple proportions states that when two elements can combine in different ratios to form different compounds, the masses of the element combining with the fixed mass of another element result in whole number ratios. This shows that the law of multiple proportions is followed

Explanation:

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A ray of white light moves through the air and strikes the surface of water in a beaker. The index of refraction of the water is
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except ii and iii

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vA 61.2-kg circus performer is fired from a cannon that is elevated at an angle of 57.8 ° above the horizontal. The cannon uses
dsp73

Answer:

The effective spring constant of the firing mechanism is 1808N/m.

Explanation:

First, we can use kinematics to obtain the initial velocity of the performer. Since we know the angle at which he was launched, the horizontal distance and the time in which it's traveled, we can calculate the speed by:

v_0_x=\frac{x}{t}\\ \\v_0\cos\theta=\frac{x}{t}\\\\v_0=\frac{x}{t\cos\theta}

(This is correct because the horizontal motion has acceleration zero). Then:

v_0=\frac{20.8m}{(2.60s)\cos57.8\°}\\\\v_0=15.0m/s

Now, we can use energy to obtain the spring constant of the firing mechanism. By the conservation of mechanical energy, considering the instant in which the elastic band is at its maximum stretch as t=0, and the instant in which the performer flies free of the bands as final time, we have:

E_0=E_f\\\\U_e=K\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\\implies k=\frac{mv^2}{x^2}

Then, plugging in the given values, we obtain:

k=\frac{(61.2kg)(15.0m/s)^2}{(2.76m)^2}\\\\k=1808N/m

Finally, the effective spring constant of the firing mechanism is 1808N/m.

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