Answer:

Explanation:
According to the Law of Conservation of Mass, the mass of the products must equal the mass of the reactants.
- mass products = mass reactants
In this problem, the reaction is:

- The reactants are iron and oxygen. We know the mass of the iron sample is 10 grams.
- The product is ferric oxide. The mass of the ferric oxide sample is 18.2 grams.

We want to find how many grams of oxygen reacted. We have to get the oxygen by itself. 10 is being added to oxygen. The inverse of addition is subtraction. Subtract 10 from both sides of the equation.



<u>8.2 grams of oxygen </u>reacted with 10 grams of iron to form 18.2 grams of ferric oxide.
Answer:
4.767 grams of KCl are produced from 2.50 g of K and excess Cl2
Explanation:
The balanced equation is
2 K+ Cl2 --->2 KCI
Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K
Mass of one atom/mole of potassium is 39.098 grams
Number of moles is 2.5 grams = 
So, 2 moles of K produces 2 moles of KCL
0.064 moles of K will produces 0.064 moles of KCl
Mass of one molecule of KCl is 74.5513 g/mol
Mass of 0.064 moles of KCl is 4.767 grams
Answer:kffffffffffffffffp;j.,,j,j[[;'/n m
Explanation:
tggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg00000000000
C = 84.71%
H = 5.88%
O = 9.41%
<h3>Further explanation</h3>
Given
3-phenylphenol, C12H10O
Required
The mass percent
Solution
Ar C = 12 g/mol
Ar H = 1 g/mol
Ar O = 16 g/mol
MW C12H10O = 170 g/mol
The mass percent :
C = (12x12/170) x 100%
C = 84.71%
H = (10x1)/170) x 100%
H = 5.88%
O = (1 x 16)/170 x 100%
O = 9.41%