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4 years ago

PLEASE HELP!! 20 POINTS!

Chemistry

1 answer:

Vinvika [58]4 years ago

3 0

Answer:

Energy transformation, also known as energy conversion, is the process of changing energy from one type of energy to another. In physics, energy is a quantity that provides the capacity to perform work (e.g. lifting an object) or provides heat. In addition to being convertible, according to the law of conservation of energy, energy is transferable to a different location or object, but it cannot be created or destroyed.

The energy in many of its forms may be used in natural processes, or to provide some service to society such as heating, refrigeration, lighting or performing mechanical work to operate machines. For example, to heat a home, the furnace burns fuel, whose chemical potential energy is converted into thermal energy, which is then transferred to the home's air to raise its temperature.

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Which of the following statements is true for an exothermic reaction

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In an exothermic reaction the energy of the product is less than the energy of the reactants.

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3 years ago

The densevapor iodinee heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid .

erma4kov [3.2K]

Explanation:

When iodine heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid. Reaction equation for the same is as follows.

$IF_{7} + 6H_{2}O \rightarrow H_{5}IO_{6} + 7HF$

As it is given that there are $3.72 \times 10^{-2}$ moles of iodine heptafluoride are present. Molar mass of $IF_{7}$ is 259.9 g/mol. Molar mass of $HIO_{4}$ is 227.94 g/mol and molar mass of HF is 20.01 g/mol.

Now, according to the reaction equation $3.72 \times 10^{-2}$ M $IF_{7}$ gives $3.72 \times 10^{-2}$ M $H_{5}IO_{6}$ .

Also, the volume is given as 795 ml or 0.795 L (as 1 mL = 0.001 L).

Hence, calculate the concentration of $H_{5}IO_{6}$ into the solution as follows.

Concentration = $\frac{\text{no. of moles}}{volume}$

= $\frac{3.72 \times 10^{-2}}{0.795 L}$

= $4.7 \times 10^{-2}$ mol/L

or, = 0.047 M

Now, as 1 mol of $IF_{7}$ produces 7 mol HF. So, $7 \times 3.72 \times 10^{-2} = 26.04 \times 10^{-2}$ M HF.

Therefore, concentration of HF will be calculated as follows.

Concentration of HF = $\frac{0.2604}{0.795}$

= 0.33 M

Thus, we can conclude that concentration of periodic acid is 0.047 M and concentration of hydrofluoric acid is 0.33 M.

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3 years ago

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Answer: it’s b)

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Answer:

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4 years ago