It increases. B.
Close to the nucleus are high energy levels, because of the pull of the nucleus. But farther away from the nucleus, the electrons there are of low energy level.
Answer is: dissolve 74,9 grams CuSO₄·5H₂O in one liter volumetric flask.
V(CuSO₄·5H₂O) = 1 L.
c(CuSO₄·5H₂O) = 0,30 mol/L.
n(CuSO₄·5H₂O) = V(CuSO₄·5H₂O) · c(CuSO₄·5H₂O) .
n(CuSO₄·5H₂O) = 1 L · 0,3 mol/L.
n(CuSO₄·5H₂O) = 0,3 mol.
m(CuSO₄·5H₂O) = n(CuSO₄·5H₂O) · M(CuSO₄·5H₂O).
m(CuSO₄·5H₂O) = 0,3 mol · 249,7 g/mol.
m(CuSO₄·5H₂O) = 74,9 g.
Answer:
4.78 g/cm³
Explanation:
Density is expressed as mass per unit volume:
D = m/V
D = (24.02 g) / (5.02 mL) = 4.78 g/mL
The density should be expressed in g/cm³, so mL must be converted to cm³. The conversion ratio is 1 mL = 1 cm³.
(4.78 g/mL)(1 mL/1 cm³) = 4.78 g/cm³
Answer:
0.217 M NaOH
Explanation:
M1V1 = M2V2
M1 = 0.312 M HCl
V1 = 17.4 mL HCl
M2 = ?
V2 = 25.0 mL NaOH
Solve for M2 --> M2 = M1V1/V2
M2 = (0.312 M)(17.4 mL) / (25.0 mL) = 0.217 M NaOH
Answer:
then it only gotta be 2 other options .
Explanation:
