<u>Answer:</u> The molarity of solution is 0.274 M and the osmotic pressure of the solution is 6.70 atm
<u>Explanation:</u>
To calculate the molarity of the solution, we use the equation:

We are given:
Given mass of estrogen = 13.5 g
Molar mass of estrogen = 272.40 g/mol
Volume of solution = 181 mL
Putting values in above equation, we get:

Hence, the molarity of solution is 0.274 M
To calculate the osmotic pressure of the solution, we use the equation:

where,
= osmotic pressure of the solution = ?
i = Van't hoff factor = 1 (for non-electrolytes)
M = molarity of solute = 0.274 M
R = Gas constant = 
T = temperature of the solution = 298 K
Putting values in above equation, we get:

Hence, the osmotic pressure of the solution is 6.70 atm