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Pavlova-9 [17]
3 years ago
9

Parker wound a wire around a large iron nail. He then created an electromagnet by connecting the ends of the wire to different b

atteries. The table shows the current he measured for each electromagnet.
Which conclusion is best supported by the data?

A) Electromagnet W is the strongest.
B) Electromagnet X is weaker than electromagnet Z.
C) Electromagnet Y is the strongest.
D) Electromagnet Y is weaker than electromagnet X.

Physics
2 answers:
torisob [31]3 years ago
8 0
Hey Ya'll its C im am correct yeah me
padilas [110]3 years ago
3 0
The correct option is C.
From the information given above, one can easily conclude that electromagnetic Y is the strongest because, it produces the higher amount of current compare to the other electromagnets. Electromagnet W is the weakest because it produces the lowest amount of current. 
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Answer:

The actual angle is 30°

Explanation:

<h2>Equation of projectile:</h2><h2>y axis:</h2>

v_y(t)=vo*sin(A)-g*t

the velocity is Zero when the projectile reach in the maximum altitude:

0=vo-gt\\t=\frac{vo}{g}

When the time is vo/g the projectile are in the middle of the range.

<h2>x axis:</h2>

d_x(t)=vo*cos(A)*t\\

R=Range

R=d_x(t=2*\frac{vo}{g})

R=vo*cos(A)*2\frac{vo}{g} \\\\R=\frac{(vo)^{2}*2* sin(A)cos(A)}{g} \\\\R=\frac{(vo)^{2} sin(2A)}{g}

**sin(2A)=2sin(A)cos(A)

<h2>The maximum range occurs when A=45°(because sin(90°)=1)</h2><h2>The actual range R'=(2/√3)R:</h2>

Let B the actual angle of projectile

\frac{vo^{2} }{g} =(\frac{2}{\sqrt{3} }) \frac{vo^{2} *sin(2B)}{g}\\\\1= \frac{2 }{\sqrt{3}} *sin(2B)\\\\sin(2B)=\frac{\sqrt{3}}{2}\\\\

2B=60°

B=30°

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Answer:

\dfrac{I_1}{I_2}=\dfrac{4}{9}

Explanation:

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Take any musical instrument with strings ... a violin, a guitar, etc.

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Twisting the peg only changed the string's tension; the length
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