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If mechanical energy is conserved in a system the energy at any point in time can be in the form of

I am Lyosha [343]

potential, kinetic, elastc energies

6 0

3 years ago

This is the substance(s) formed in a chemical reaction.

vfiekz [6]

This is the substance(s) formed in a chemical reaction. is called the products

8 0

3 years ago

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If an object falls for 4 seconds, how fast is it going when it hits the ground?

MArishka [77]

Acceleration due to gravity is about 9.8 m/s²

So after every second, the speed increase by 9.8 m/s

After 1 second, the object would fall at a speed of 9.8 m/s

After 2 seconds the object would fall at a speed of 19.6 m/s

So after 4 seconds, the object is going to be at a speed of:

9.8 x 4 = 39.2 m/s

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<u>Answer</u>

39.2 m/s

3 0

4 years ago

Select the community facility which usually has a driving range on the property to practice your swing.

vagabundo [1.1K]

Answer:

golf course

Explanation:

i will give you all the answers you desire, my love

3 0

3 years ago

Scientists are working on a new technique to kill cancer cells by zapping them with ultrahigh-energy (in the range of 1012 W) pu

Tcecarenko [31]

1. $7.95\cdot 10^6 J$

The total energy given to the cells during one pulse is given by:

$E=Pt$

where

P is the average power of the pulse

t is the duration of the pulse

In this problem,

$P=1.59\cdot 10^{12}W$

$t=5.0 ns = 5.0\cdot 10^{-9} s$

Substituting,

$E=(1.59\cdot 10^{12}W)(5.0 \cdot 10^{-6}s)=7.95\cdot 10^6 J$

2. $1.26\cdot 10^{21}W/m^2$

The energy found at point (1) is the energy delivered to 100 cells. The radius of each cell is

$r=\frac{4.0\mu m}{2}=2.0 \mu m = 2.0\cdot 10^{-6}m$

So the area of each cell is

$A=\pi r^2 = \pi (2.0 \cdot 10^{-6}m)^2=1.26\cdot 10^{-11} m^2$

The energy is spread over 100 cells, so the total area of the cells is

$A=100 (1.26\cdot 10^{-11} m^2)=1.26\cdot 10^{-9} m^2$

And so the intensity delivered is

$I=\frac{P}{A}=\frac{1.59\cdot 10^{12}W}{1.26\cdot 10^{-9} m^2}=1.26\cdot 10^{21}W/m^2$

3. $9.74\cdot 10^{11} V/m$

The average intensity of an electromagnetic wave is related to the maximum value of the electric field by

$I=\frac{1}{2}c\epsilon_0 E^2$

where

c is the speed of light

$\epsilon_0$ is the vacuum permittivity

E is the amplitude of the electric field

Solving the formula for E, we find:

$E=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(1.26\cdot 10^{21} W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12}F/m)}}=9.74\cdot 10^{11} V/m$

4. 3247 T

The magnetic field amplitude is related to the electric field amplitude by

$E=cB$

where

E is the electric field amplitude

c is the speed of light

B is the magnetic field

Solving the equation for B and substituting the value of E that we found at point 3, we find

$B=\frac{E}{c}=\frac{9.74\cdot 10^{11} V/m}{3\cdot 10^8 m/s}=3247 T$

3 0

3 years ago

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