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ale4655 [162]
2 years ago
7

Maganda ka Tapos Liit mopa​

Physics
1 answer:
kirza4 [7]2 years ago
5 0

Answer:

naol may pinoy dito nag jakoI

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For this trajectory, what would the vertical component of acceleration for the module be at time tm=t0−σ=325s? Recall that accel
Karo-lina-s [1.5K]
I think its half of pie so you divid that by 3.14 .
4 0
3 years ago
Read 2 more answers
A student wants to create a 6.0V DC battery from a 1.5V DC battery. Can this be done using a transformer alone
shusha [124]

Answer:

Therefore, we need an invert, and a rectifier, along with the transformer to do the job.

Explanation:

A transformer, alone, can not be used to convert a DC voltage to another DC voltage. If we apply a DC voltage to the primary coil of the transformer, it will act as short circuit due to low resistance. It will cause overflow of current through winding, resulting in overheating pf the transformer.

Hence, the transformer only take AC voltage as an input, and converts it to another AC voltage. So, the output voltage of a transformer is also AC voltage.

So, in order to convert a 6 V DC to 1.5 V DC we need an inverter to convert 6 V DC to AC, then a step down transformer to convert it to 1.5 V AC, and finally a rectifier to convert 1.5 V AC to 1.5 V DC.

<u>Therefore, we need an invert, and a rectifier, along with the transformer to do the job.</u>

8 0
2 years ago
Transformer is used in rectifier step up and step down voltage?<br>​
tensa zangetsu [6.8K]

Answer:

While the use of the type of transformer in a rectifier depends on the voltage requirement or to meet desired operating conditions, a step-down transformer is used mainly to reduce the voltage. It is used to bring the high AC voltage level to a reasonable value or the desired output voltage.

Explanation:

Hope it helps

Correct me if Im wrong

3 0
2 years ago
Plz help me and thx if you do!
Rina8888 [55]
I think it’s b... not sure tho sorry
3 0
2 years ago
An object travels with velocity v = 4.0 meters/second and it makes an angle of 60.0° with the positive direction of the y-axis.
zhenek [66]

Answer:

2 m/s and -2 m/s

Explanation:

The object travels with an angle of

60.0°

with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).

If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:

v_x = v cos \theta = (4.0 m/s) cos 60.0^{\circ}=2 m/s

If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:

v_x = -v cos \theta = -(4.0 m/s) cos 60.0^{\circ}=-2 m/s

5 0
3 years ago
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