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3 years ago

What is the momentum of a 950 kg car moving at 10.0 m/s?

Physics

2 answers:

KonstantinChe [14]3 years ago

6 0

What's 950 x 10 bro?

9500 kg m/s

OverLord2011 [107]3 years ago

6 0

Answer:

Momentum of the car, p = 9500 kg-m/s.

Explanation:

It is given that,

Mass of the car, m = 950 kg

Velocity of the car, v = 10 m/s

We need to find the momentum of the car. It is given by the product of mass and velocity. It is given by :

$p=m\times v$

$p=950\ kg\times 10\ m/s$

p = 9500 kg-m/s

So, the momentum of the car is 9500 kg-m/s. Hence, this is the required solution.

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Max ran 100 feet in 10 seconds.

Ivanshal [37]

Answer:

for max :

100 feet in 10 secs

for molly :

60 feet in 5 secs = 120 feet in 10 secs

so, molly ran farther in the same time interval i.e. covered 120 feet where as Max covered 100 feet

Explanation:

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3 years ago

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What is the Genetic Modification Process? Brainlyist for the best answer

Dovator [93]

Answer:

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3 years ago

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Charge g is distributed in a spherically symmetric ball of radius a. (a) Evaluate the average volume charge density p. (b) Now a

nasty-shy [4]

Answer:

Explanation:

The volume of a sphere is:

V = 4/3 * π * a^3

The volume charge density would then be:

p = Q/V

p = 3*Q/(4 * π * a^3)

If the charge density depends on the radius:

p = f(r) = k * r

I integrate the charge density in spherical coordinates. The charge density integrated in the whole volume is equal to total charge.

$Q = \int\limits^{2*\pi}_0\int\limits^\pi_0 \int\limits^r_0 {k * r} \, dr * r*d\theta* r*d\phi$

$Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0 \int\limits^r_0 {r^3} \, dr * d\theta* d\phi$

$Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0 {\frac{r^4}{4}} \, d\theta* d\phi$

$Q = k *\int\limits^{2*\pi}_0 {\frac{\pi r^4}{4}} \, d\phi$

$Q = \frac{\pi^2 r^4}{2}}$

Since p = k*r

Q = p*π^2*r^3 / 2

Then:

p(r) = 2*Q / (π^2*r^3)

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3 years ago

17. Which of the following is the closest weight in newtons of a 7.0-kilogram

marusya05 [52]

Weight = (mass) x (gravity)

Weight = (7.0 kg) x (gravity)

On Earth, where (gravity) is roughly 10 N/kg . . .

Weight = (7.0 kg) x (roughly 10 N/kg)

Weight = roughly 70 Newtons

That's B on Earth.

It would be some other number on other bodies.

4 0

3 years ago

It takes 1 minute for 45 c to pass a point in a circuit, what is the current flowing through the circuit?

ohaa [14]

Answer:

0.75 A

Explanation:

An electric current is a flow of charged particles.

A current is defined through its intensity, which is given by:

$I=\frac{q}{t}$

where

I is the current intensity

q is the charge passing through a given point in the circuit

t is the time it takes for the charge q to pass that point in the circuit

In this problem, we have:

q = 45 C is the charge passing through the point in the circuit

$t=1 min = 60 s$ is the time elapsed

Therefore, the current intensity is:

$I=\frac{45}{60}=0.75 A$

5 0

3 years ago