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saw5 [17]
3 years ago
9

What is the momentum of a 950 kg car moving at 10.0 m/s?

Physics
2 answers:
KonstantinChe [14]3 years ago
6 0
What's 950 x 10 bro?
<span>
9500 kg m/s
</span>
OverLord2011 [107]3 years ago
6 0

Answer:

Momentum of the car, p = 9500 kg-m/s.

Explanation:

It is given that,

Mass of the car, m = 950 kg

Velocity of the car, v = 10 m/s

We need to find the momentum of the car. It is given by the product of mass and velocity. It is given by :

p=m\times v

p=950\ kg\times 10\ m/s

p = 9500 kg-m/s

So, the momentum of the car is 9500 kg-m/s. Hence, this is the required solution.

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According to the quantum theory of radiation,
masya89 [10]

Answer:

Option B

Explanation:

According to quantum theory of radiation electromagnetic field or electromagnetic  radiation( like light) produce by accelerated charge object and the quantum of EM radiations is photon which has discrete energy. So, EM field can have only certain values of total energy and no other value due the discrete nature of the energy of photon. Hence option B is correct

4 0
3 years ago
Please help me!!!!!!!! it's due soon!!!!!!!!!!!!! NO LINK!!!!!!!!!
maria [59]
.75(m/s)^2


Use this picture
If you know the two on the bottom you multiply them but if you only know the top and one on the bottom you divide

7 0
3 years ago
An atom that no longer has a beutral charge is called a(n)____.
Simora [160]

An atom that no longer has a neutral charge is called an ion

8 0
3 years ago
Two objects are dropped from different heights at the same instant. If the first object takes 10.7 seconds to hit the ground and
Lubov Fominskaja [6]

Answer:

The answer to your question is : 521.8 m

Explanation:

Data:

Different heights

Time first object (tfo) = 10.7 s

Time second object (tso)= 14.8 s

Initial speed of both objects(vo) = 0 m/s

a = 9.81 m/s²

Formula:

h = vot + 1/2 (a)(t)² but vo = 0    so, h = 1/2 (a)(t)²

Then, height fo      h = 1/2 (9.81)(10.7)² = 561.6 m

          height so     h = 1/2(9,81)(14.8)² = 1074.4 m

Difference in their heights =  1074.4 m - 561.6 m = 521.8 m

5 0
3 years ago
There is an analogy between rotational and linear physical quantities. what rotational quantities are analogous to distance and
SVEN [57.7K]

ANSWER:

Angular displacement is analogous to distance.

Angular velocity is analogous to velocity.

EXPLANATION:

FOR  ANGULAR DISPLACEMENT AND DISTANCE

Angular displacement = theta

theta = s/r

s = linear dispalcement/distance

r= radius.

so ,

linear displacement/distance  s = theta * r.

FOR  ANGULAR VELOCITY AND VELOCITY

Angular velocity = w

w = v/r

v = velocity

r = radius

so,

velocity v = w * r.

5 0
3 years ago
Read 2 more answers
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