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saw5 [17]
3 years ago
9

What is the momentum of a 950 kg car moving at 10.0 m/s?

Physics
2 answers:
KonstantinChe [14]3 years ago
6 0
What's 950 x 10 bro?
<span>
9500 kg m/s
</span>
OverLord2011 [107]3 years ago
6 0

Answer:

Momentum of the car, p = 9500 kg-m/s.

Explanation:

It is given that,

Mass of the car, m = 950 kg

Velocity of the car, v = 10 m/s

We need to find the momentum of the car. It is given by the product of mass and velocity. It is given by :

p=m\times v

p=950\ kg\times 10\ m/s

p = 9500 kg-m/s

So, the momentum of the car is 9500 kg-m/s. Hence, this is the required solution.

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A car travels up a hill at a constant speed of 38 km/h and returns down the hill at a constant speed of 66 km/h. Calculate the a
mojhsa [17]

Answer:

Average speed will be 48.23 km/h

Explanation:

Let the distance up to hill is = d km

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So time required t=\frac{distance}{speed}=\frac{d}{38}hour

Speed when car return from hill = 66 km/h

So time required to return fro hill t=\frac{d}{66}h

Total time t_{total}=\frac{t}{38}+\frac{t}{66}

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8 0
3 years ago
En un m.A.S. La amplitud tiene un valor de 10 centimetros y el periodo es de 2 segundos calcular el valor de la velocidad de 0.8
Ivanshal [37]

Answer:

v1=18.46m/s

v2=29.8cm/s

Explanation:

We know that

A=10cm\\T=2s

the equation of the motion is

x=Acos(\omega t)\\

we can calculate w by using

\omega=\frac{2\pi}{T}=\frac{2\pi}{2}=\pi

Hence, we have that

x=10cm*cos(\pi t)\\

the speed will be

v=-\omega*Asin(\omega t)\\|v(0.8)|=|\pi*10cm*sin(\pi *0.8)|=18.46\frac{cm}{s}\\|v(1.4)|=|\pi*10cm*sin(\pi *1.4)|=29.8\frac{cm}{s}

hope this helps!

6 0
3 years ago
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