when 6.25 grams of pure iron are allowed to react with oxygen , a black oxide forms. if the product weighs 8.15 g, what is the e
1 answer:
You might be interested in
Answer : The value of equilibrium constant (K) is, 424.3
Explanation : Given,
Concentration of at equilibrium = 0.067 mol
Concentration of at equilibrium = 0.021 mol
Concentration of at equilibrium = 0.040 mol
The given chemical reaction is:
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
Thus, the value of equilibrium constant (K) is, 424.3
Answer:
Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
element & mass %
phosphorus & 39.18%
sulfur & 60.82%
Write the molecular formula of X.
Explanation:
The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.
Empirical formula calculation:
element: phosphorus sulfur
co9mposition: 39.185% 60.82%
divide with
atomic mass: 39.185/31.0 g/mol 60.82/32.0g/mol
=1.26mol 1.90mol
smallest mole ratio: 1.26mol/1.26mol =1 1.90mol/1.26 mol =1.50
multiply with 2: 2 3
Hence, the empirical formula is:
P2S3.
Mass of empirical formula is:
158.0g/mol
Given, molecule has molar mass --- 316.25 g/mol
Hence, the ratio is:
316.25g/mol/158.0 =2
Hence, the molecular formula of the compound is :
2 x (P2S3)
=
This is an incomplete question, here is a complete question and an image is attached below.
The following diagrams represent mixtures of NO(g) and O₂(g). These two substances react as follows:
It has been determined experimentally that the rate is second order in NO and first order in O₂.
Based on this fact, which of the following mixtures will have the fastest initial rate?
The mixture (1). The mixture (2). The mixture (3).
Answer : The mixture 1 has the fastest initial rate.
Explanation :
The given chemical reaction is:
The rate law expression is:
Now we have to determine the number of molecules of
In mixture 1 : There are 5 and 4
molecules.
In mixture 2 : There are 7 and 2
molecules.
In mixture 3 : There are 3 and 5
molecules.
Now we have to determine the rate law expression for mixture 1, 2 and 3.
The rate law expression for mixture 1 is:
The rate law expression for mixture 2 is:
The rate law expression for mixture 3 is:
Hence, the mixture 1 has the fastest initial rate.
