Answer: 9.9 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
1 mole of combine with 1 mole of
Thus 0.33 mole of will combine with =
mole of
Thus is the limiting reagent as it limits the formation of product.
As 1 mole of give = 1 mole of
Thus 0.33 moles of give =
of
Mass of
Thus theoretical yield (g) of produced by the reaction is 9.9 grams
Answer : The volume of solution required is, 2.93 L
The number of moles of formed from the reaction is, 0.662 moles.
Explanation :
First we have to calculate the initial moles of .
Now we have to calculate the moles of
The balanced chemical reaction is:
From the balanced chemical reaction we conclude that,
As, 1 mole of react with 2 moles of
So, 0.662 mole of react with
moles of
Now we have to calculate the volume of
Now we have to calculate the moles of
From the balanced chemical reaction we conclude that,
As, 1 mole of react to give 1 moles of
So, 0.662 mole of react to give 0.662 moles of
Thus, the number of moles of formed from the reaction is, 0.662 moles.