Answer:
127°C
Explanation:
This excersise can be solved, with the Charles Gay Lussac law, where the pressure of the gas is modified according to absolute T°.
We convert our value to K → -73°C + 273 = 200 K
The moles are the same, and the volume is also the same:
P₁ / T₁ = P₂ / T₂
But the pressure is doubled so: P₁ / T₁ = 2P₁ / T₂
P₁ / 200K = 2P₁ / T₂
1 /2OOK = (2P₁ / T₂) / P₁
See how's P₁ term is cancelled.
200K⁻¹ = 2/ T₂
T₂ = 2 / 200K⁻¹ → 400K
We convert the T° to C → 400 K - 273 = 127°C
Answer: 
iron atoms
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 
of particles.
![1 molecule of [tex]Fe_2O_3](https://tex.z-dn.net/?f=1%20molecule%20of%20%5Btex%5DFe_2O_3)
contains= 2 atoms of iron
![1 mole of [tex]Fe_2O_3](https://tex.z-dn.net/?f=1%20mole%20of%20%5Btex%5DFe_2O_3)
contains=
atoms of iron
thus 0.32 moles of 
contains=
atoms of iron
Thus the sample would have iron atoms.
N2(g)+3H2 >>>>>2NH3(g)
the mole ratio between N2, H2 and NH3. It is 1 : 3 : 2
mole N2 present
moles H2 present = 25.0 g H2 x 1 mole H2/2 g = 12.5 moles H2 present
Based on mole ratio, N2 is limiting in this situation because there is more than enough H2 but not enough N2.
moles NH3 that can be produced = 1 mole N2 x 2 moles NH3/mole N2 = 2 moles NH3 can be produced
grams of NH3 that can be produced = 2 moles NH3 x 17 g/mole = 34 grams of NH3 can be produced
<span>Conservation of energy. A ball rolls down a ramp, then up another ramp. Even if the ramps are set at different angles, the final height achieved by the ball is (almost) its original height.</span>
