Given:
<span>BaO2(s) + 2 HCl(aq) => H2O2(aq) + BaCl2(aq)
</span>
Mass of barium peroxide = 1.49 g Volume of HCl solution = 25.1 mLConcentration of HCl solution = 0.0279 g HCl per mL
Solution: To determine the amount of hydrogen peroxide that would be produced, we use need to determine which is the limiting reactant and use the initial amount of this reactant for the calculations.
0.0279 g HCl / mL ( 25.1 mL ) ( 1 mol HCl / 36.46 g HCl) ( 1 mol BaO2 / 2 mol HCl ) = 0.0096 mol BaO2 needed
1.49 g BaO2 ( 1 mol / 169.3 g BaO2 ) ( 2 mol HCl / 1 mol BaO2 ) = 0.0176 mol HCl needed
Therefore, the limiting reactant would be barium peroxide since it is consumed completely first in the reaction.
1.49 g BaO2 ( 1 mol BaO2 / 169.3 g BaO2 ) ( 1 mol H2O2 / 1 mol BaO2 ) ( 34.02 g H2O2 / 1 mol H2O2 ) = 0.299 g H2O2
C because it’s reshaping it, it stays the same but just reshaping it
Answer:
5150 kPa
Explanation:
Given that,
Initial volume, V₁ = 100 mL
Initial pressure, P₁ = 103 kPa
Final volume, V₂ = 2 mL
We need to find the new pressure of the gas. The relation between the pressure and the volume of gas is given by :
So, the new pressure is 5150 kPa.
Answer:
Explanation:
glucose-1-phosphate → glucose-6-phosphate, ΔGo = -7.28 kJ/mol
fructose-6-phosphate → glucose-6-phosphate, ΔGo = -1.67 kJ/mol
subtracting the equation
glucose-1-phosphate - fructose-6-phosphate = 0 , ΔGo = -7.28 - ( -1.67 ) kJ / mol
glucose-1-phosphate = fructose-6-phosphate ΔGo = - 5.61 kJ / mol
- ΔGo = RT lnK
5.61 x 10³ = 8.31 x 298 x lnK
lnK = 2.265
K = 9.63 .
Answer:
Ionic solids
Explanation: Ionic solids—Made up of positive and negative ions and held together by electrostatic attractions. They're characterized by very high melting points and brittleness and are poor conductors in the solid state. An example of an ionic solid is table salt, NaCl.
