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amid [387]
3 years ago
13

Calculate the no. of moles in 25gm of calcium phosphate Plz Fast Urgent

Chemistry
1 answer:
madreJ [45]3 years ago
7 0

Answer:

0.162 mol

Explanation:

n=m/M

M= 20*3 + 15*2 + 8*4*2

M=154 g/mol

n=25g/154g/mol

n=0.162 mol

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For the reaction KClO2⟶KCl+O2 KClO2⟶KCl+O2 assign oxidation numbers to each element on each side of the equation. K in KClO2:K i
frosja888 [35]

Answer:

Explanation:

The formula of the reaction:

            KClO₂ → KCl + O₂

To assign oxidation numbers, we have to obey some rules:

  1. Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
  2. The charge on simple ions signifies their oxidation number.
  3. The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.

The oxidation number of K in KClO₂:

                                   K + (-1) + 2(-2) = 0

                                    K-5 = 0

                                    K = +5

The oxidation number of K in KCl:

                                K + (-1) = 0

                                K = +1

The oxidation number Cl in KClO₂ is -1

For Cl in KCl, the oxidation number is -1

For O in KClO₂, the oxidation number is (2 x -2) = -4

For O in O₂, the oxidation number is 0

K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.

O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.

7 0
3 years ago
Read 2 more answers
How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
GuDViN [60]

Answer:

41.17g

Explanation:

We are given the following parameters for Flourine gas(F2).

Volume = 5.00L

Pressure = 4.00× 10³mmHG

Temperature =23°c

The formula we would be applying is Ideal gas law

PV = nRT

Step 1

We find the number of moles of Flourine gas present.

T = 23°C

Converting to Kelvin

= °C + 273k

= 23°C + 273k

= 296k

V = Volume = 5.00L

R = 0.08206L.atm/mol.K

P = Pressure (in atm)

In the question, the pressure is given as 4.00 × 10³mmHg

Converting to atm(atmosphere)

1 mmHg = 0.00131579atm

4.00 × 10³ =

Cross Multiply

4.00 × 10³ × 0.00131579atm

= 5.263159 atm

The formula for number of moles =

n = PV/RT

n = 5.263159 atm × 5.00L/0.08206L.atm/mol.K × 296K

n = 1.0834112811moles

Step 2

We calculate the mass of Flourine gas

The molar mass of Flourine gas =

F2 = 19 × 2

= 38 g/mol

Mass of Flourine gas = Molar mass of Flourine gas × No of moles

Mass = 38g/mol × 1.0834112811moles

41.169628682grams

Approximately = 41.17 grams.

3 0
2 years ago
• Find the Percentage Composition for CO
Aleks04 [339]

Answer:

Carbon or the symbol C has a mass percentage of 42.880% while Oxygen or symbol O has a mass percentage of 57.120%

4 0
2 years ago
Read 2 more answers
Please help me thank you so much <3
Goshia [24]

Answer:

answer: they seek to produce verficiable data.

7 0
2 years ago
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What is the significance of equivalence point in acid base titrations?
iren2701 [21]

Hey there!

The equivalence is point in a titration is the point at which you have neutralized all of your base/acid with your titrant acid/base from a buret. This can be seen with indicators which change color at the equivalence point in a titration to signal to you that all of your base/acid has been reacted with. For example, all your molecules of OH⁻ from a NaOH base in a beaker have been neutralized by H⁺of HCl acid from your titrant in a buret leaving only Na⁺ ions and Cl⁻ ions and neutral H₂O molecules.

7 0
3 years ago
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