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amid [387]
3 years ago
13

Calculate the no. of moles in 25gm of calcium phosphate Plz Fast Urgent

Chemistry
1 answer:
madreJ [45]3 years ago
7 0

Answer:

0.162 mol

Explanation:

n=m/M

M= 20*3 + 15*2 + 8*4*2

M=154 g/mol

n=25g/154g/mol

n=0.162 mol

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How many moles of SO2 will be produced from 11.5 moles of O2?
pshichka [43]

Explanation:

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8 0
3 years ago
If the molar absorptivity constant for the red dye solution is 5.56×104 M-1cm-1, calculate the molarity of the red dye solution
Shtirlitz [24]

Explanation:

a) Using Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

where,

A = absorbance of solution = 0.945

c = concentration of solution = ?

l = length of the cell = 1.20 cm

\epsilon = molar absorptivity of this solution =5.56\times 10^4 M^{-1} cm^{-1}

0.945=5.56\times 10^4 M^{-1} cm^{-1}\times 1.20 \times c

c=1.4163\times 10^{-5} M=14.16 \mu M

(1\mu M=10^{-6} M)

14.16 μM is the molarity of the red dye solution at the optimal wavelength 519nm and absorbance value 0.945.

b) c=1.4163\times 10^{-5} mol/L

1 L of solution contains 1.4163\times 10^{-5} moles of red dye.

Mass of 1.4163\times 10^{-5} moles of red dye:

1.4163\times 10^{-5}\times 879.86g/mol=0.01246 g

(w/v)\%=\frac{\text{Mass of solute (g)}}{\text{Volume of solvent (mL)}}\times 100

red(w/v)\%=\frac{0.01246 g}{1000 mL}\times 100=0.001246\%

c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.

Concentration of red dye solution = c=1.4163\times 10^{-5} M

Concentration of red solution after dilution = c'

c=c'\times 5

1.4163\times 10^{-5} M=c'\times 5

c'=2.83\times 10^{-6} M

The final concentration of the diluted solution is 2.83\times 10^{-6} M

8 0
3 years ago
The ph of a certain orange juice is 3.36. calculate the h ion concentration.
Citrus2011 [14]
PH=-log[H⁺]
[H⁺]= 10^{-pH} =10^{-3.36} =4.36*10^{-4}M
6 0
3 years ago
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