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3 years ago

If my friend have the corona what do I do

Engineering

2 answers:

nordsb [41]3 years ago

5 0

(E. Call the hospital to take them away

Fiesta28 [93]3 years ago

4 0

Answer:E

Explanation:

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A fan that consumes 20 W of electric power when operating is claimed to discharge air from a ventilated room at a rate of 1.0 kg

solong [7]

Answer:

No, the claim is not reasonable for 20 W electric power consumption.

It is reasonable for 40 W electric power consumption.

Explanation:

Power = (1/2)*mass flow rate*(square of velocity)

mass flow rate = 1 kg/s

velocity = 8 m/s

square of velocity = 64 m^2 / s^2

Power = (1/2)*(1)*(64)

Power = 32 W

For a fan that consumes 20 W power it is not possible to deliver more power than 20 W but this one is delivering 32 W hence it is a false claim.

For a fan that consumes 40 W it is indeed possible to deliver 32 W considering the efficiency. Hence this claim is reasonable.

5 0

3 years ago

THE COMPUND INTEREST ON RS 30,000AT 7% PER ANNUM IS RS 4347 THE PERIOD IN YEARS

timofeeve [1]

Answer:

what wym

Explanation:

4 0

3 years ago

Read 2 more answers

Write a simple phonebook program that reads in a series of name-number pairs from the user (that is, name and number on one line

Vlad1618 [11]

Answer:

import java.util.HashMap;

import java.util.Map;

import java.util.Scanner;

public class PhoneBook {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

Map<String, String> map = new HashMap<>();

String name, number, choice;

do {

System.out.print("Enter name: ");

name = in.next();

System.out.print("Enter number: ");

number = in.next();

map.put(name, number);

System.out.print("Do you want to try again(y or n): ");

choice = in.next();

} while (!choice.equalsIgnoreCase("n"));

System.out.print("Enter name to search for: ");

name = in.next();

if (map.containsKey(name)) {

System.out.println(map.get(name));

} else {

System.out.println(name + " is not in the phone book");

}

6 0

3 years ago

A Carnot cycle is to be designed to attain

Anni [7]

Answer:

reservoir is 727°C, then low temperature

Explanation:

Efficiency for any Heat engine = Work done by engine / Heat provided to the engine

Also, for a carnot engine derived formula for Carnot Engine

= 1- T2/T1

Where, T2 = sink reservoir temperature

and T1 = source reservoir temperature

727° C = 1000 K

So, 0.75 = 1-T2 / 1000

So, T2 = 1000*0.25 = 250 K = -23 Kelvin

8 0

3 years ago

Air fl ows isentropically through a duct. At section 1, the pressure and temperature are 250 kPa and 1258C, and the velocity is

abruzzese [7]

The correct temperature is 125°C

Answer:

A) M_a1 = 0.5

B) T2 = 232.17 K

C) V2 = 611 m/s

D) m' = 187 kg/s

Explanation:

We are given;

Pressure; P1 = 250 kPa

Temperature; T1 = 125°C = 398 K

Speed; v1 = 200 m/s

Area; A2 = 0.25 m²

M_a2 = 2

A) Formula for M_a1 is given by;

M_a1 = v/a1

Where;

v is speed

a1 = √kRT

k is specific heat capacity ratio of air = 1.4

R is a gas constant with a value of R = 287 J/kg·K

T is temperature

Thus;

M_a1 = 200/√(1.4 × 287 × 398)

M_a1 = 200/399.895

M_a1 = 0.5

B) To find T2, let's first find the Stagnation pressure T0

Thus;

T0/T1 = 1 + ((k - 1)/2) × (M_a1)²

T0 = T1(1 + ((k - 1)/2) × (M_a1)²)

T0 = 398(1 + ((1.4 - 1)/2) × (0.5)²)

T0 = 398(1 + (0.2 × 0.5²))

T0 = 398 × 1.05

T0 = 417.9 K

Now,similarly;

T0/T2 = 1 + ((k - 1)/2) × (M_a2)²

T2 = T0/[(1 + ((k - 1)/2) × (M_a2)²)]

T2 = 417.9/(1 + (0.2 × 2²))

T2 = 417.9/1.8

T2 = 232.17 K

C) V2 is gotten from the formula;

T0 = T2 + (V2)²/(2C_p)

Cp of air = 1005 J/Kg.K

Thus;

V2 = √(2C_p)[T0 - T2]

V2 = √((2 × 1005) × (417.9 - 232.17))

V2 =√373317.3

V2 = 611 m/s

D) mass flow is given by the formula;

m' = ρA2•V2

Where;

ρ is Density of air with an average value of 1.225 kg/m³

m' = 1.225 × 0.25 × 611

m' = 187 kg/s

6 0

3 years ago