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3 years ago

Select three types of lines that engineers use to help represent the shape of a design in a sketch.

Engineering

1 answer:

Vikki [24]3 years ago

7 0

Hidden lines

Used to describe the in shown lines (like diagonals inside cubes)

Extension lines:-

Used to explain the expansion of structures like building

Object lines

Used to describe the structure of objects and the lining to show borders

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Oxygen enters an insulated 14.2-cm-diameter pipe with a velocity of 60 m/s. At the pipe entrance, the oxygen is at 240 kPa and 2

MatroZZZ [7]

Answer:

Entropy generation==0.12 KW/K

Explanation:

$s_2-s_1=C_p\ln \frac{T_2}{T_1}-R\ln \frac{P_2}{P_1}$

$s_2-s_1=0.891\ln \frac{291}{293}-0.2598\ln \frac{200}{240}$

$s_2-s_1=0.0412\frac{KJ}{kg-K}$

Mass flow rate= $\rho\times\dfrac{\pi}{4}d^2V$

$\rho_1=\dfrac {P_1}{RT_1}$

$\rho_1=\dfrac {240}{0.2598\times 293}$

$\rho_1=3.51\frac{kg}{m^3}$

mass flow rate= $\rho_1A_1V_1$

So by putting the values

Mass flow rate=2.97 kg/s

So entropy generation=(2.97)(0.0412)

=0.12 KW/K

8 0

4 years ago

Describe how you might use the concept of parts presentation to help a classroom full of children complete a craft project. Disc

Ket [755]

Answer:

Encouraging your preschooler’s creative play

For your preschooler, time, materials and space to be creative are very important.

Preschoolers like to be spontaneous in their creative play, so it’s good to follow your child’s lead. But there’ll also be times when your child wants you to be more involved in her creative activities. By being actively involved, you can develop your child’s skills and understanding.

3 0

3 years ago

An isentropic steam turbine processes 2 kg/s of steam at 3 MPa, which is exhausted at50 kPa and 100C. Five percent of this flow

borishaifa [10]

Answer:

2285kw

Explanation:

since it is an isentropic process, we can conclude that it is a reversible adiabatic process. Hence the energy must be conserve i.e the total inflow of energy must be equal to the total outflow of energy.

Mathematically,

$\\ E_{inflow} = E_{outflow}$

Note: from the question we have only one source of inflow and two source of outflow (the exhaust at a pressure of 50kpa and the feedwater at a pressure of 5ookpa). Also the power produce is another source of outgoing energy $\\ E_{inflow} = m_{1} h_{1}$ .

$\\$

$E_{outflow} = m_{2} h_{2} + m_{3} h_{3} + W_{out}$

$\\$

Where $m_{1} h_{1}$ are the mass flow rate and the enthalpies at the inlet at a pressure of 3Mpa $\\$ ,

$m_{2} h_{2}$ are the mass flow rate and the enthalpies at the outlet 2 where we have a pressure of 500kpa respectively. $\\$ ,

and $m_{3} h_{3}$ are the mass flow rate and the enthalpies at the outlet 3 where we have a pressure of 50kpa respectively. $\\$ ,

We can now express write out the required equation by substituting the new expression for the energies $\\$

$m_{1} h_{1} = m_{2} h_{2} + m_{3} h_{3} + W_{out}$ $\\$

from the above equation, the unknown are the enthalpy values and the mass flow rate. $\\$

first let us determine the enthalpy values at the inlet and the out let using the Superheated water table. $\\$

It is more convenient to start from outlet 3 were we have a temperature $100^{0}C$ and pressure value of (50kpa or 0.05Mpa ). using double interpolation method on the superheated water table to determine the enthalpy value with careful calculation we have $\\$

$h_{3}$ = 2682.4 KJ/KG , at this point also from the table the entropy value , $s_{3}$ value is 7.6953 KJ/Kg.K. $\\$

Next we determine the enthalphy value at outlet 2. But in this case, we don't have a temperature value, hence we use the entrophy value since the entropy is constant at all inlet and outlet. $\\$

So, from the superheated water table again, at a pressure of 500kpa (0.5Mpa) and entropy value of 7.6953 KJ/Kg.K with careful interpolation we arrive at a enthalpy value of 3206.5KJ/Kg. $\\$

Finally for inlet one at a pressure of 3Mpa, interpolting with an entropy value of 7.6953KJ/Kg.K we arrive at enthalpy value of 3851.2KJ/Kg. $\\$

Now we determine the mass flow rate at each inlet and outlet. since mass must also be balance, i.e $m_{1} = m_{2} + m_{3}$ $\\$

From the question the, the mass flow rate at the inlet $m_{1}}$ is 2Kg/s $\\$

Since 5% flow is delivered into the feedwater heating, $\\$

$m_{2} = 0.05m_{1} = 0.05 *2kg/s = 0.1kg/s$ $\\$

Also for the outlet 3 the remaining 95% will flow out. Hence

$m_{3} = 0.95m_{1} = 0.95 *2kg/s = 1.9kg/s$ $\\$

Now, from $m_{1} h_{1} = m_{2} h_{2} + m_{3} h_{3} + W_{out}$ $\\$ we substitute values

$W_{out} = m_{1} h_{1}-m_{2} h_{2}-m_{3} h_{3}$

$W_{out} = (2kg/s)(3851.2KJ/Kg) - (0.1kg/s)(3206.5kJ/kg)- (1.9)(2682.4kJ/kg)$

$\\$

$W_{out} = 2285.19 kW$ .

Hence the power produced is 2285kW

7 0

3 years ago

You recall an algorithm from elementary school for factoring a number N: Divide out all factors of 2, then of 3, then of 4, then

Contact [7]

Answer:

let number = 0

while number < 1

begin

print "Enter a positive integer: "

read number

end

end_while

find and print number's factors:

let prime = TRUE

let currentFactor = 2

let lastFactor = the square root of number truncated

to an integer value

while currentFactor <= lastFactor

begin

if number is evenly divisible by currentFactor

begin

print currentFactor

let number = number / currentFactor

end

else

let currentFactor = currentFactor + 1

end_if

end

end_while

print a message if number is prime:

if prime == TRUE

print "Your number is prime"

end_if

Explanation:

4 0

3 years ago

Who would need to be consulted when specifying the requirements of a project?

elena55 [62]

Answer:A technology expert

Explanation:

3 0

3 years ago