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Rus_ich [418]
4 years ago
12

Can you please help me it’s due at 11:59 please

Physics
1 answer:
antoniya [11.8K]4 years ago
4 0

Answer:

1 is summer, 2 is most likely winter,3 is most likely summer, and 4 is fall

Explanation:

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For each telecommunications bonding conductor there shall be a label and it shall be located on the conductor as close as practi
shepuryov [24]

Answer:

There shall be a LABEL

Explanation:

The label is to enable the maintenance personal or the user to identify the individual conductor from each other during removal and installation or when maintenance task is being carried out on the system. This is to avoid the users of the system form plugging the conductor incorrectly.

For example, if there are four conductors label A, B, C, and D there will be four connection point label same way. By this, the user will not plug conductor A to plug B.

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4 years ago
A student uses a spring with a spring constant of 130 N/m in his projectile apparatus. When 56 J of
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Explanation:

potentional \: energy \:  =  \frac{1}{2} k {x}^{2}  \\ 56 =  \frac{1}{2}  \times 130 \times  {x}^{2}  \\  {x}^{2}  =  \frac{56}{65}  \\ x =  \sqrt{ \frac{56}{65} } meter

plz..

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4 0
3 years ago
Which is larger: a megawatt or a kilowatt? how many times larger is it
Mandarinka [93]
A megawatt is larger than a kilowatt. The scientific notation for kilo is 10 to the 3, meaning 1000. A mega is 10 to the 6, meaning one million. That means a kilo watt is a thousand watts, and mega is a million watts
5 0
3 years ago
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Explain the function and the difference between figure 1 and 2
natita [175]

Answer:

figure one (step up transformer) helps in increasing the output voltage

figure two (step down transformer) helps in decreasing the output voltage

8 0
2 years ago
A piano tuner stretches a steel piano wire with a tension of 1070 N . The wire is 0.400 m long and has a mass of 4.00 g . A. Wha
pychu [463]

A. 409 Hz

The fundamental frequency of a string is given by:

f_1=\frac{1}{2L}\sqrt{\frac{T}{m/L}}

where

L is the length of the wire

T is the tension in the wire

m is the mass of the wire

For the piano wire in this problem,

L = 0.400 m

T = 1070 N

m = 4.00 g = 0.004 kg

So the fundamental frequency is

f_1=\frac{1}{2(0.400)}\sqrt{\frac{1070}{(0.004)/(0.400)}}=409 Hz

B. 24

For this part, we need to analyze the different harmonics of the piano wire. The nth-harmonic of a string is given by

f_n = nf_1

where f_1 is the fundamental frequency.

Here in this case

f_1 = 409 Hz

A person is capable to hear frequencies up to

f = 1.00 \cdot 10^4 Hz

So the highest harmonics that can be heard by a human can be found as follows:

f=nf_1\\n= \frac{f}{f_1}=\frac{1.00\cdot 10^4}{409}=24.5 \sim 24

8 0
4 years ago
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