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3 years ago

Can you please help me it’s due at 11:59 please

Physics

1 answer:

antoniya [11.8K]3 years ago

4 0

Answer:

1 is summer, 2 is most likely winter,3 is most likely summer, and 4 is fall

Explanation:

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A copper wire 20 m long and 4mm in diameter is attached to the Ceiling and a 400 N

Fiesta28 [93]

Answer:

Explanation:

5 0

2 years ago

A baseball thrown from the outfield to home plate does not have which of the following types of energy while it's in the air? A.

posledela

The ball does not have D. Radiant energy.

7 0

3 years ago

A boy with a mouse is 80 kg stands on a scale in an ascending elevator with an acceleration of 3 m/s What is the resultant upwar

Rus_ich [418]

Answer:

Upward force on the boy will be 1024 N

Explanation:

We have given mass of the boy m = 80 kg

Acceleration due to gravity $g=9.8m/sec^2$

It is given that elevator is ascending with acceleration of $3m/sec^2$

So net acceleration on the boy = 9.8+3 = 12.8 $m/sec^2$ ( As the car elevator is moving ascending )

So upward force on the boy will be equal to F = m(g+a)

So $F=80\times 12.8=1024N$

So upward force on the boy will be 1024 N

3 0

3 years ago

A quantity of a gas has an absolute pressure of 400 kPa and an absolute temperature of 110 degrees kelvin. When the temperature

shepuryov [24]

You can make sure there's no change in volume by keeping
your gas in a sealed jar with no leaks. Then you can play with
the temperature and the pressure all you want, and you'll know
that the volume is constant.

For 'ideal' gases,

   (pressure) times (volume) is proportional to (temperature).

And if volume is constant, then

   (pressure) is proportional to (temperature) .

So if you increase the temperature from 110K to 235K,
the pressure increases to (235/110) of where it started.

   (400 kPa) x (235/110) = 854.55 kPa. (rounded)

Obviously, choice-b is the right one, but
I don't know where the .46 came from.

4 0

3 years ago

A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.2 rad/s in 3.07 s. (a) f

Hitman42 [59]

(a) The angular acceleration of the wheel is given by
$\alpha = \frac{\omega_f - \omega_i }{t}$
where $\omega_i$ and $\omega_f$ are the initial and final angular speed of the wheel, and t the time.

In our problem, the initial angular speed is zero (the wheel starts from rest), so the angular acceleration is
$\alpha = \frac{(11.2 rad/s) - 0}{3.07 s} =3.65 rad/s^2$

(b) The wheel is moving by uniformly rotational accelerated motion, so the angle it covered after a time t is given by
$\theta (t) = \omega_i t + \frac{1}{2} \alpha t^2$
where $\omega_i = 0$ is the initial angular speed. So, the angle covered after a time t=3.07 s is
$\theta= \frac{1}{2} \alpha t^2 = \frac{1}{2}(3.65 rad/s^2)(3.07 s)^2 = 17.2 rad$

6 0

3 years ago