The molar mass of methylammonium bromide is 111u.
<h3>What is molar mass?</h3>
The molar mass is defined as the mass per unit amount of substance of a given chemical entity.
Multiply the atomic weight (from the periodic table) of each element by the number of atoms of that element present in the compound.
Add it all together and put units of grams/mole after the number.
Atomic weight of H is 1u
Atomic weight of N is 14u
Atomic weight of C is 12u
Atomic weight of Br is 79u
Calculating molar mass of 
=2(1 x3+ 14+12+ 1 x 3 +79) = 111u
Hence, the molar mass of methylammonium bromide is 111u.
Learn more about molar mass here:
brainly.com/question/12127540
#SPJ1
Answer:
K₂CrO₅
Explanation:
The empirical formula is the simplest formula of a compound. To find the empirical formula, we follow the procedure below:
Elements Potassium Chromium Oxygen
Mass 6.52 4.34 5.34
Molar mass 39 60 16
Number of moles 6.52/39 4.34/60 5.34/16
0.167 0.072 0.333
Divide through by
the smallest 0.167/0.072 0.072/0.072 0.333/0.072
2.3 1 4.6
2 1 5
Empirical formula K₂CrO₅
Answer:
The energy of a wave is inversely proportional to the wavelength of the wave.
As wavelength increases, the energy of the wave decreases.
As wavelength decreases, the energy of the wave increases.
Explanation:
The energy of a wave is directly proportional to the wave's frequency. As frequency increases, so does the energy of the wave.
(energy 
is proportional to frequency 
)
<u>How is this related to wavelength?</u>
Frequency is inversely proportional to wavelength. That means that as frequency increases, wavelength decreases and as frequency decreases, wavelength increases.
(frequency is inversely proportional to wavelength 
)
Therefore, as wavelength increases, the energy of a wave decreases and as wavelength decreases, the energy of a wave increases.
Answer:
Explanation:
Given data:
Mass of calcium oxide = 14.4 g
Mass of carbon dioxide = 13.8 g
Actual yield of calcium carbonate = 19.4 g
Mass of calcium carbonate produced = ?
Limiting reactant = ?
Percent yield = ?
Chemical equation:
CaO + CO₂ → CaCO₃
Number of moles of CaO:
Number of moles of CaO = Mass /molar mass
Number of moles of CaO = 14.4 g / 56.1g/mol
Number of moles of CaO = 0.26 mol
Number of moles of CO₂:
Number of moles of CO₂= Mass /molar mass
Number of moles of CO₂ = 13.8 g / 44 g/mol
Number of moles of CO₂ = 0.31 mol
Now we will compare the moles of CaCO₃ with CO₂ and CaO.
CaO : CaCO₃
1 : 1
0.26 : 0.26
CO₂ : CaCO₃
1 : 1
0.31 : 0.31
The number of moles of CaCO₃ produced by CaO are less it will be limiting reactant.
Limiting reactant:
CaO
Theoretical yield:
Mass of CaCO₃ = moles × molar mass
Mass of CaCO₃ = 0.26 mol × 100 g/mol
Mass of CaCO₃ = 26 g
Percent yield:
Percent yield = Actual yield / theoretical yield × 100
Percent yield = 19.4 g/ 26 g× 100
Percent yield = 74.6 %
Answer:THIS IS NOT THE ANSWER
is this for the chemistry A final 10th grade for connexus (unit7 lesson 2)?
Explanation:
