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arlik [135]
3 years ago
6

    Which of these is considered a cation

Chemistry
1 answer:
olganol [36]3 years ago
6 0
It is C. Cations have positive charge. They get a positive charge when they lose an electron in their outer shell
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Explain how natural resources are identified and why natural recourses are in evenly distributed.
mixer [17]

Answer:

Natural resources are not evenly distributed all over the world. Some places are more endowed that others — for instance, some regions have lots of water (and access to ocean and seas). Others have lots of minerals and forestlands. Others have metallic rocks, wildlife, fossil fuels and so on.

Explanation:

3 0
3 years ago
What is a carbohydrate?​
bogdanovich [222]

Answer:

Burned Energy

Explanation:

Energy that burns

6 0
3 years ago
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7. Bananas contain potassium. Which form of potassium is most likely found in bananas or in nature? a. K atom b. K+ cation C. K-
bulgar [2K]

Answer:

B. K+cation

Explanation:

Not all that sure but hope it will help.

7 0
3 years ago
Problem Page Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 70. g of
shusha [124]

Answer:

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}

Explanation:

1. Write down the balanced chemical reaction:

2C_{6}H_{14}_{(l)}+19O_{2}_{(g)}=12CO_{2}_{(g)}+14H_{2}O_{(g)}

2. Find the limiting reagent:

- First calculate the number of moles of hexane and oxygen with the mass given by the problem.

For the hexane:

70.0gC_{6}H_{14}*\frac{1molC_{6}H_{14}}{86.2gC_{6}H_{14}}=0.81molesC_{6}H_{14}

For the oxygen:

81.3gO_{2}*\frac{1molO_{2}}{32.0gO_{2}}=2.54molesO_{2}

- Then divide the number of moles between the stoichiometric coefficient:

For the hexane:

\frac{0.81}{2}=0.41

For the oxygen:

\frac{2.54}{19}=0.13

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.

3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:

The calculations must be done with the limiting reagent, that is the oxygen.

81.3gO_{2}*\frac{1molO_{2}}{32gO_{2}}*\frac{12molesCO_{2}}{19molesO_{2}}*\frac{44.0gCO_{2}}{1molCO_{2}}=70.6gCO_{2}

7 0
3 years ago
according to Boyles law if the initial pressure and volume of a gas were five atm for the pressure and 10 mL for the volume and
maks197457 [2]

Answer:The new volume is 5mL

Explanation:

The formular for Boyles Law is; P1 V1 = P2 V2

Where P1 = 1st Pressure   V1 = First Volume

          P2 = 2nd Pressure V2 = Second Volume

From the question; P1 = 5atm, V1 = 10ml

                                P2 = 2 x P1 (2 x 5) = 10 atm   V2 =?  

Using the Boyles Law Formular;  P1 V1 = P2 V2, we make V2 the subject of formular;  P1 V1/ P2 = V2

∴ 5 x 10/ 10 = 5

∴ V2 = 5mL

5 0
3 years ago
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