Hello!
1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?
- <u><em>We have the following data:</em></u>
Vo (initial volume) = 1.00 L
V (final volume) = 473 mL → 0.473 L
Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)
P (final pressure) = ? (in atm)
- <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>
<u><em>Answer: </em></u>
<u><em>The new pressure of the gas is 2.11 atm </em></u>
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Momentum = (mass) x (velocity) = (1,100) x (30) =
33,000
kg-m/sec due east
Answer:
Electrons
Explanation:
Atoms can combine together and share electrons between them. Atoms that share electrons are linked to each other in a form, called a molecule that is in a lower energy state than either of the separate atoms alone.
Pls Brainliest! It would mean a lot! ;)
Answer:
0.55 atm
Explanation:
First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by
where
m = 1.00 g is the mass of the gas
Mm = 44.0 g/mol is the molar mass of the gas
Substituting,
Now we can find the pressure of the gas by using the ideal gas law:
where
p is the gas pressure
V = 1.00 L is the volume
n = 0.0227 mol is the number of moles
R = 0.082 L/(atm K mol) is the gas constant
T = 25.0 C + 273 = 298 K is the temperature of the gas
Solving the formula for p, we find
