In order to solve this, we need to know the standard cell potentials of the half reaction from the given overall reaction.
The half reactions with their standard cell potentials are:
<span>2ClO−3(aq) + 12H+(aq) + 10e- = Cl2(g) + 6H2O(l)
</span><span>E = +1.47
</span>
<span>Br(l) + 2e- = 2Br-
</span><span>E = +1.065
</span>
We solve for the standard emf by subtracting the standard emf of the oxidation from the reducation, so:
1.47 - 1.065 = 0.405 V
Well this is a bio question but it goes the tunica interna the tunica media then the tunica externa.
Answer:
Fe(s) → Fe²⁺(aq) + 2e⁻ OXIDATION
Mg²⁺(aq) + 2e⁻ → Mg(s) REDUCTION
Explanation:
The redox reaction is: MgCl₂(aq) + Fe(s) → FeCl₂(aq) + Mg(s)
We need to know that elements in ground state have 0 as the oxidation state.
Iron in the reactants, and Mg in the products
In the magnessium chloride, the Mg acts with+2, so the oxidation state has decreased → REDUCTION
In the iron(II) chloride, the Fe acts with +2, so the oxidation statehas increased → OXIDATION
The half reactions are:
Fe(s) → Fe²⁺(aq) + 2e⁻ OXIDATION
Mg²⁺(aq) + 2e⁻ → Mg(s) REDUCTION
Answer:
Data supports significantly because we can use the testing(depending sample) before and after we use the same object to test the hypothesis.
I would say the correct answer would probably be that to explain the approx 100 years between Dalton (early 1800's) atomic theory and JJ Thomson's discovery of the smaller particle the electron was that Thomson had the use of a cathode ray tube that helped to determine the existence of negatively charged particles about 2000 times lighter than a hydrogen atom and therefore a smaller particle than the atom. The cathode ray tube was not invented until 1897, when Thomson began experimenting with it.
