Heat gained by ice cubes would be equal to the - heat lost by warm water
The moles of ice is: 50.5 g / 18.0 g/mol = 2.81 mol
Heat required to melt all of the ice is equal to: 2.81 mol X 6.02 kJ/mol = 16.9 kJ = 16890 J
Now, know whether the warm water will still be above 0C when it loses this much heat:
-1690 J = 160 g (4.184 J/gC) (Delta T) Delta T = -25C
In order to solve for the final temperature, going back to include warming of the melted ice to a final temperature:
q(ice/water) = - q(warm water)
moles (Delta Hf) + m c (T2-T1) = - m c (T2-T1)
50.5 g / 18.0 g/mol = 2.81 mol
2.81 mol X 6.02 kJ/mol + 50.5g (4.184 J/gC) (T2-0) = -160g (4.184 J/gC) ( T2-80)
16916 + 211.3T2 = -669.4 T2 + 53555
36639 = 880.7 T2
T2 = 41.6 C
the value of delta H° for aniline = -3201. 5 Kj/mol
<u><em> calculation</em></u>
Step 1: find heat
Q ( heat) = C ( specific heat capacity) x ΔT ( change in temperature)
C= 4.25 kj/c°
ΔT = 69.8-29.5 = 40.3 c°
Q= 4.25 kj/c x 40.3 c = 171.28 kj
Step 2: find the moles of aniline
moles = mass/ molar mass
= 4.98 g/ 93.13 g/mol =0.0535 moles
Step 3 : find delta H
171.28 kj / 0.0535=3201.5 kj/mol
since the reaction is exothermic delta H = -3201.5 Kj/mol
Answer:
Maybe you could do something with nuclear power plants and how we use those to create electrical energy for our phones, houses etc?
Explanation:
उत्तर : गुरुत्वाकर्षण का सार्वत्रिक नियम :
इस विश्व का प्रत्येक पिंड दूसरे पिंड को एक बल से अपनी ओर आकर्षित करता है जो दोनों पिंडों के द्रव्यमानों के गुणनफल के समानुपाती होता है तथा उनके बीच की दूरी के वर्ग के व्युत्क्रमानुपाती होता
