Answer:
p2 = 9.8×10^4 Pa
Explanation:
Total pressure is constant and PT = P = 1/2×ρ×v^2
So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2
from continuity we have ρ×A1×v1 = ρ×A2×v2
v2 = v1×A1/A2
and
r2 = 2×r1
then:
A2 = 4×A1
so,
v2 = (v1)/4
then:
p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2
p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)
= 9.75×10^4 Pa
= 9.8×10^4 Pa
Therefore, the pressure in the wider section is 9.8×10^4 Pa
"Life is wasted if we do not grasp the glory of the cross, cherish it for the treasure that it is, and cleave to it as the highest price of every pleasure and the deepest comfort in every pain. What was once foolishness to us—a crucified God—must become our wisdom and our power and our only boast in this world.” - John Piper
T=5s
S=5m
U=0s/m
Acceleration=m/s^2
S=ut+(1/2)(a)(5^2)
A=(25/2)=5
A=5/(25/2)
A=10/25
A=2/5
A=0.4
A=0.4m/s^2.
A good diet. and exersise is the answer
<u><em>Answer:</em></u>
Momentum of the skier is 350 Kg.m/sec
<u><em>Explanation:</em></u>
<u>Momentum of a body can be calculated using the following rule:</u>
P = m * v
<u>where:</u>
P is the momentum of the body
m is the mass of the body given as 70 Kg
v is the velocity of the body given as 5 m/sec
<u>Substitute with the givens in the above rule to get the momentum of the skier as follows:</u>
P = m * v
P = 70 * 5
P = 350 Kg.m/sec
Hope this helps :)
