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dsp73
3 years ago
11

which statement below is FALSE? A Gravity acts on any object with mass. B The closer objects are, the stronger the gravitational

force between them. C The farther you are from the center of the Earth, the less gravitational force you feel. D Gravitational force depends on what the object is made of.
Physics
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

Explanation:

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How does wavelength change as frequency increases? A) Wavelength increases as frequency increases. B) Wavelength decreases as fr
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Wavelength decreases as frequency increases
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Energy a substance or system has because of its motion Is what?
iragen [17]

Answer:

The answer is Mechanical Energy

8 0
2 years ago
A positive charge, q1, of 5 µC is 3 × 10–2 m west of a positive charge, q2, of 2 µC. What is the magnitude and direction of the
belka [17]
We know, F = 1/4πε * q₁q₂ / r²
Here, q₁ = 5 * 10⁻⁶ C
q₂ = 2 * 10⁻⁶ C
r = 3 * 10⁻² m west

Substitute their values, 
F = (9 * 10⁹) (5 * 10⁻⁶) (2 * 10⁻⁶)  / (3 * 10⁻²)²

F = 100 N  [ East of positive charge ]

Hope this helps!
5 0
3 years ago
Read 2 more answers
A two-slit pattern is viewed on a screen 1.26 m from the slits. If the two fourth-order maxima are 53.6 cm apart, what is the to
Anettt [7]

Answer:

= 6.55cm

Explanation:

Given that,

distance = 1.26 m

distance between  two fourth-order maxima = 53.6 cm

distance between central bright fringe and fourth order maxima

y = Y / 2

  =  53.6cm / 2

  = 26.8 cm

  =0.268 m

tan θ = y / d

         = 0.268 m /  1.26 m

         = 0.2127

       θ = 12°

4th maxima

d sinθ = 4λ

d / λ = 4 / sinθ

d / λ = 4 / sin 12°

d / λ = 19.239

for first (minimum)

d sinθ = λ / 2

sinθ =  λ / 2d

       =  1 / 2(19.239)

       = 1 / 38.478

       = 0.02599

    θ =  1.489°

tan θ = y / d

y = d tan θ

  = 1.26 tan 1.489°

  = 0.03275

the total width of the central bright fringe  

Y = 2y

  = 2(0.03275)

  = 0.0655m

  = 6.55cm

4 0
3 years ago
The cue ball is deflected so that it makes an angle of 30.0° with its original direction of travel.
Alexus [3.1K]

Answer:

(a) θ= 43.89°

(b) v_{1} = 1.88\sqrt{3} \frac{m}{s}

    v_{2} = 6.79 \frac{m}{s}

Explanation:

Ball 1:

u_{1} = 7.52\frac{m}{s}

Ball 2:

u_{2} = 0\frac{m}{s}

As the collision is elastic, it means that kinetic energy and momentum are conserved. Following that, we apply the law of conservation of energy and momentum:

\frac{1}{2} m_{1}u_{1}^{2}   = \frac{1}{2} m_{1}v_{1}^{2} + \frac{1}{2} m_{2}v_{2}^{2}

and

m_{1}u_{1} =   m_{1}v_{1} + m_{2}v_{2}

Where u is the velocity before the collision, and v are the velocities after the collision. Both previous equations can be simplified as:

u_{1}^{2}   = v_{1}^{2} + v_{2}^{2}

and

u_{1} =   v_{1} + v_{2}

This because the two balls have the same mass. We know that the cue ball is deflected and makes an angle of 30°. From conservation in x-direction, we get::

56.55 = v_{1} ^{2} + v_{2} ^{2}

and

u_{1} = v_{1}cos(30) +  v_{2}cos(\theta)

Solving we get:

(\frac{2u_{1}-\sqrt{3}v_{1}  }{2cos(\theta)})^{2}  = 56.55-v_{1} ^{2}

From conservation in y-direction, we get:

0 = v_{1}sin(30) -  v_{2}sin(\theta)

From this, we solve this equation system and get the answers. Remember to add 30° to the angle obtained.

8 0
3 years ago
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