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r-ruslan [8.4K]
3 years ago
12

An instrument that measures wind speed is called a(n ________.

Physics
1 answer:
Oduvanchick [21]3 years ago
7 0
The instrument that measures wind is called anemometer. Anemometer not only measures wind, but also, this measures the direction of the wind. And anemometer is also a common device used in a station weather. It is dervived from the greek work anemos which means wind.
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[The illustration shows a lamp giving off light. What form of energy does the lamp use to produce light?
AnnZ [28]

Answer:

I think it's electrical energy

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Can an electron be found in an exact spot within an atom
jolli1 [7]
No, it is impossible to determine the exact location of an electron. This is because electrons don't have a definite position, and direction of motion, at the same time and its movements are unpredictable
3 0
3 years ago
It takes 185 kj of work to accelerate a car from 23.0 m/s to 28.0 m/s. what is the car's mass?
Pachacha [2.7K]
<span>This question is based on conservation of energy as the work done would lead to change in kinetice energy of car change in KE = 1/2 mv(f)^2 - 1/2mv(i)^2 = 1/2m(v(f)^2-v(i)^2) where v(f) and v(i) are the final and initial speeds change in KE = 185kJ = 185,000J = 1/2 m((28m/s)^2-(23m/s)^2) 185,000=1/2 m(255m^2/s^2) solving for m m=1451kg</span>
6 0
3 years ago
8. An unpowered flywheel is slowed by a constant frictional torque. At time t = 0 it has an angular velocity of 200 rad/s. Ten s
allsm [11]

Answer:

a) \omega = 50\,\frac{rad}{s}, b) \omega = 0\,\frac{rad}{s}

Explanation:

The magnitude of torque is a form of moment, that is, a product of force and lever arm (distance), and force is the product of mass and acceleration for rotating systems with constant mass. That is:

\tau = F \cdot r

\tau = m\cdot a \cdot r

\tau = m \cdot \alpha \cdot r^{2}

Where \alpha is the angular acceleration, which is constant as torque is constant. Angular deceleration experimented by the unpowered flywheel is:

\alpha = \frac{170\,\frac{rad}{s} - 200\,\frac{rad}{s} }{10\,s}

\alpha = -3\,\frac{rad}{s^{2}}

Now, angular velocities of the unpowered flywheel at 50 seconds and 100 seconds are, respectively:

a) t = 50 s.

\omega = 200\,\frac{rad}{s} - \left(3\,\frac{rad}{s^{2}} \right) \cdot (50\,s)

\omega = 50\,\frac{rad}{s}

b) t = 100 s.

Given that friction is of reactive nature. Frictional torque works on the unpowered flywheel until angular velocity is reduced to zero, whose instant is:

t = \frac{0\,\frac{rad}{s}-200\,\frac{rad}{s} }{\left(-3\,\frac{rad}{s^{2}} \right)}

t = 66.667\,s

Since t > 66.667\,s, then the angular velocity is equal to zero. Therefore:

\omega = 0\,\frac{rad}{s}

7 0
3 years ago
A stone is thrown horizontally at 30m/s from a tall cliff.
Jobisdone [24]

x(2) = 30(2) = 60 m

y(2) = ½(-9.8)2² = -19.6 m

x(4) = 30(4) = 120 m

y(4) = ½(-9.8)4² = -78.4 m

x(6) = 30(6) = 180 m

y(6) = ½(-9.8)6² = -176.4 m

x(8) = 30(8) = 240 m

y(8) = ½(-9.8)8² = -313.6 m

x(10) = 30(10) = 300 m

y(10) = ½(-9.8)10² = -490 m

5 0
3 years ago
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