Answer:
0 m/s²
Explanation:
Since each skater pushes the other with a force of 70 N, according to Newton's third law, there is an equal reaction and thus the other pushes back with a force of 70 N in the other direction, so we have forces of +70N and -70 N respectively. So, the net force on each skateboarder is F = + 70 N + (-70 N) = + 70 N - 70 N = 0 N.
Since force, F = ma where a = acceleration and m = mass,
a = F/m.
So, since for each skater, F = 0N,
a = 0 N/m
= 0 m/s²
So, the acceleration of each skater is 0 m/s²
Answer:
First Condition of Equilibrium is that it must be experiencing no acceleration or the external forces acting on the body should be zero.
<h3>Question:</h3>
How to find g (acceleration due to gravity)
<h3>Solution:</h3>
We know,
Acceleration due to gravity (g)
![= \frac{GM}{ {R}^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7BGM%7D%7B%20%7BR%7D%5E%7B2%7D%20%7D%20)
where, G = Gravitational constant
![= 6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \\](https://tex.z-dn.net/?f=%20%3D%206.67%20%5Ctimes%20%20%7B10%7D%5E%7B11%7D%20N%20%7Bm%7D%5E%7B2%7D%2Fk%20%7Bg%7D%5E%7B2%7D%20%20%5C%5C%20)
M = Mass of the earth
![= 6 \times {10}^{24} \: kg](https://tex.z-dn.net/?f=%20%3D%206%20%5Ctimes%20%20%7B10%7D%5E%7B24%7D%20%5C%3A%20%20kg)
R = Radius of the earth
![= 6.4 \times {10}^{6} m](https://tex.z-dn.net/?f=%20%3D%206.4%20%5Ctimes%20%20%7B10%7D%5E%7B6%7D%20m)
Putting these values of G, M and R in the above formula, we get
![g \: = \: \frac{6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \times \: 6 \times {10}^{24} \: kg }{(6.4 \times {10}^{6}m {)}^{2} } \\ = 9.8m/ {s}^{2}](https://tex.z-dn.net/?f=g%20%5C%3A%20%20%3D%20%20%5C%3A%20%20%5Cfrac%7B6.67%20%5Ctimes%20%20%7B10%7D%5E%7B11%7D%20N%20%7Bm%7D%5E%7B2%7D%2Fk%20%7Bg%7D%5E%7B2%7D%20%20%20%5Ctimes%20%5C%3A%206%20%5Ctimes%20%20%7B10%7D%5E%7B24%7D%20%5C%3A%20%20kg%20%7D%7B%286.4%20%5Ctimes%20%20%7B10%7D%5E%7B6%7Dm%20%7B%29%7D%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%3D%209.8m%2F%20%7Bs%7D%5E%7B2%7D%20)
So, the value of acceleration due to gravity is
![9.8m/s ^{2}](https://tex.z-dn.net/?f=9.8m%2Fs%20%5E%7B2%7D%20)
Hope it helps.
Do comment if you have any query.
Are you referring to the fact that water is a compound while hydrogen is an element? If I'm wrong just comment and clarify and I can edit it, I don't even know what kind of unit you're in. :)
Answer:
c) L³/T³
Explanation:
If t stands for time, the units are:
(V) = L³, (t) = T
The units for the equation:
V(t) = At³
must be:
![L^{3} = \frac{L^{3} }{T^{3}} T^{3}](https://tex.z-dn.net/?f=L%5E%7B3%7D%20%3D%20%5Cfrac%7BL%5E%7B3%7D%20%7D%7BT%5E%7B3%7D%7D%20T%5E%7B3%7D)