Question

An apple falls out of a tree and takes 1.75 seconds to strike the ground.what was the velocity of the apple when it hit the ground

Answer 1

Assuming acceleration is 10
let the final velocity be x
(x-0) /1.75= 10 where 0 is initial velocity at its highest point
x= 17.5m/s

Answer 2

Answer:

$v_f=17.15\frac{m}{s}$

Explanation:

The apple is in free fall, therefore we can use the kinematic equations, especifically the which one that relate final speed to acceleration of gravity and time:

$g=\frac{v_f-v_o}{t}$

The initial speed is zero, since falls out of the tree and recall that $g=9.8\frac{m}{s^2}$. So, Rewriting for final speed:

$v_f=gt\\v_f=(9.8\frac{m}{s^2})(1.75s)\\v_f=17.15\frac{m}{s}$