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vlabodo [156]
3 years ago
10

What’s the most density thing out of

Chemistry
1 answer:
Oksanka [162]3 years ago
7 0

Answer:

Iron is the densest out of the given options.

Explanation:

Oxygen

1.429 g/L

Water

1000 g/L

Hydrogen Peroxide

1450 g/L

Iron

7874 g/L

Iron Oxide

5240 g/L

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Compare the costs of using renewable resources to the costs of using nonrenewable resources.
Vitek1552 [10]

Answer:

Sample response:

The costs of using both renewable and nonrenewable resources depend on the extent of the use. If renewable resources are managed wisely, the use of the resource will not exceed the rate at which it is replenished. In this instance the cost of using renewable resources can be minimized, if not entirely eliminated. The cost of using nonrenewable resources is harder to minimize because nonrenewable resources cannot be replenished at the rate at which they are used. The environmental impact of using nonrenewable resources such as fossil fuels is greater than just the loss of the resource itself. Other impacts such as acid rain, global warming, and atmospheric pollution can result from the use of nonrenewable resources.

Explanation:

2021 edge

have a nice day

8 0
2 years ago
Read 2 more answers
Reliable results are results that can be...<br> A: communicated<br> B: evaluated<br> C: duplicated
insens350 [35]
Reliable results are results that can be... A: Communicated
4 0
3 years ago
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Ag2S + Al(s) = Al2S3 + Ag(s) (unbalanced)
Dovator [93]

Answer:

1. 0.97 V

2. Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/Ag_(_s_)

Explanation:

In this case, we can start with the <u>half-reactions</u>:

Ag^+~_(_a_q_)->~Ag_(_s_)

Al_(_s_)~->~Al^+^3~_(_a_q_)

With this in mind we can <u>add the electrons</u>:

Ag^+~_(_a_q_)+~e^-~->~Ag_(_s_)  <u>Reduction</u>

Al_(_s_)~->~Al^+^3~_(_a_q_)+~3e^-~ <u>Oxidation</u>

The reduction potential values for each half-reaction are:

Ag_2S~+~e^-~->~Ag_(_s_)~+~S^-^2~_(_a_q_) - 0.69 V

Al^+^3~_(_a_q_)+~2e^-~->~Al_(_s_) -1.66 V

In the aluminum half-reaction, we have an oxidation reaction, therefore we have to <u>flip</u> the reduction potential value:

Al_(_s_)~->~Al^+^3~+~2e^-~ +1.66 V

Finally, to calculate the overall potential we have to <u>add</u> the two values:

1.66 V - 0.69 V = <u>0.97 V</u>

For the second question, we have to keep in mind that in the cell notation we put the anode (the oxidation half-reaction) in the left and the cathode (the reduction half-reaction) in the right. Additionally, we have to use "//" for the salt bridge, therefore:

Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/~Ag_(_s_)

I hope it helps!

3 0
3 years ago
If 60.2 grams of hg combines completely with 24.0 grams of br to form a compound what is the percent
NikAS [45]

Answer is: the percent composition of Hg in the compound is 71.5%.

Balanced chemical reaction: Hg + Br₂ → HgBr₂.

m(Hg) = 60.2 g; mass of the mercury.

m(Br₂) = 24.0; mass of the bromine.

m(HgBr₂) = m(Hg) + m(Br₂).

m(HgBr₂) = 60.2 g + 24 g.

m(HgBr₂) = 84.2 g; mass of the compound.

ω(Hg) = m(Hg) ÷ m(HgBr₂) · 100%.

ω(Hg) = 60.2 g ÷ 84.2 g · 100%.

ω(Hg) = 71.5%.

6 0
3 years ago
Read 2 more answers
The blood cells that directly attack germs are: *​
irga5000 [103]

Answer:

lymphocytes

Explanation:

it consists of the b and the t cells

4 0
3 years ago
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