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mihalych1998 [28]
4 years ago
7

A cylindrical beam of electric charge flows with uniform velocity u⃗ =10z^ [m/s] The beam's axis is the z^-axis, and it has a ra

dius of r=0.8 [meters] and it has a charge density of rhov=−3r2 [C/m3] Calculate the net electric charge flux (the net current) flowing in the +z^-direction through the z=0 plane. Give the answer in units of [A]. Give three significant figures.
Physics
1 answer:
Likurg_2 [28]4 years ago
8 0

Answer:

Net electric charge flux is 19.30.

Explanation:

Velocity u =10 z

Charge density ,ρv = - 3r²

r= 0.8 m

The net electric charge given as

n.e.c.=\oint \rho_v.u.ds

u .ds= 10 dA

Now by putting the values

n.e.c.=\int_{0}^{2\pi}\int_{0}^{0.8}-3r^2.10r.dr.d\theta

n.e.c.=-30\int_{0}^{2\pi}\int_{0}^{0.8}r^3dr.d\theta

n.e.c.=2\pi\left(\dfrac{30r^4}{4}\right)_0^{0.8}\\

n.e.c.=2\pi\left(\dfrac{30\times (0.8)^4}{4}\right)

n.e.c=19.30

So the net electric charge flux is 19.30.

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Speed of air = 1106.38 ft/s

Explanation:

Speed of sound in air with temperature

v_{air}=331.3\sqrt{1+\frac{T}{273.15}} \\

Here speed is in m/s and T is in celcius scale.

T = 50°F

T=(50-32)\times \frac{5}{9}=10^0C \\

Substituting

v_{air}=331.3\sqrt{1+\frac{10}{273.15}}=337.31m/s \\

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v_{air}=337.31\times 3.28=1106.38ft/s \\

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In a football game, a 90 kg receiver leaps straight up in the air to catch the 0.42 kg ball the quarterback threw to him at a vi
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To solve this problem it is necessary to apply the equations related to the conservation of momentum. Mathematically this can be expressed as

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A police radar gun uses X-band microwave radiation at a frequency of 12.2 GHz. Microwaves travel at the speed of light, or 3x108
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Answer:

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A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 4.00 m/s, and
Svetlanka [38]

Answer:

a = 1.152s

b = 0.817 m

c = 7.29m/s

Explanation: let the following

From the first equation of linear motion

V = u+at..........1

parameters be represented as :

t = Time taken

v = Final velocity

a = Acceleration due to gravity = 9.8m/s²

u = Initial velocity = 4 m/s

s = Displacement

V = 0

Substitute the values into equation 1

0 = 4-9.8(t)

-4 = -9.8t

t = 4/9.8

t = 0.408s

From : s = ut+1/2at^2.........2

S = 4×0.408+0.5(-9.8)×0.408^2

S= 1.632-4.9(0.166)

S = 1.632-0.815

S = 0.817m

Her highest height above the board is 0.817 m

Total height she would fall is 0.817+1.90 = 2.717 m

From equation 2

s = ut+1/2at^2

2.717 m = 0t+0.5(9.8)t^2

2.717 m = 0+4.9t^2

2.717 m = 4.9t^2

2.717/4.9 = t^2

0.554 =t^2

t =√0.554

t = 0.744s

Hence, her feet were in the air for 0.744+0.408seconds

= 1.152s

Also recall from equation 1

V= u+at

V = 0+9.8(0.744)

V = 7.29m/s

Hence, the velocity when she hits the water is 7.29m/s

Finally,

a = 1.152s

b = 0.817 m

c = 7.29m/s

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