a motor pulls up a block suspended on a string, so that the tension in the string is equal to the qeight force on the block. the
1 answer:
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Answer:
10.22 cm
Explanation:
linear charge density, λ = 7.5 x 10^-12 C/m
distance from line, r = 14.5 cm = 0.145 m
initial speed, u = 3000 m/s
final speed, v = 0 m/s
charge on proton, q = 1.6 x 10^-19 C
mass of proton, m = 1.67 x 10^-27 kg
Let the closest distance of proton is r'.
The potential due t a line charge at a distance r' is given by
where, K = 9 x 10^9 Nm^2/C^2
W = q V
By use of work energy theorem
Work = change in kinetic energy
By substituting the values, we get
r' = 14.5 x 0.7047 = 10.22 cm
Answer:
10,035
Explanation:
Length of the beam is 3.2m
Mass of steel beam is 500kg
Weight of steel =mg
Ws=400×9.8=4900N
Also, man of mass =70kg
Weight of man(Wm)=70×9.8=686N
The weight of the man will act as the middle of the beam
Torque is given as Force ×distance
tnet=Wm×L + Ws×L/w
tnet=686×3.2+4900×1.6
tnet=10,035.2Nm
The net torque about where the beam is bolted is 10,035.2Nm
Check attachment for diagram
