If forces acting on an object are unbalanced, the object could experience a change in _______

Un barco va a una velocidad de 45 ml/h, luego el capitán ordena acelerar hasta que la velocidad hasta que la velocidad sea de 60

Sophie [7]

Pregunta completa:

Un barco va a una velocidad de 45 ml/h, luego el capitán ordena acelerar hasta que la velocidad hasta que la velocidad sea de 60 mll/h. si la operación dura 30 minutos.

A cual fue la aceleracion?

B qué distancia recorre?

Responder:

30 millas / hora

26.25 mi

Explicación:

Dado que :

Velocidad inicial, u = 45 mi / hr

Velocidad final, v = 60 mi / hr

Tiempo, t = 30 minutos = 30/60 = 0,5 h

Aceleración, a = cambio de velocidad con el tiempo;

a = (v - u) / t

a = (60 - 45) / 0,5

a = 15 / 0,5

a = 30 millas / h²

Recorrido de distancia, S

S = ut + 0.5at²

S = 45 (0,5) + 0,5 (30) (0,5²)

S = 22,5 + 3,75

S = 26,25 millas

4 0

3 years ago

16 grams of ice at –32°C is to be changed to steam at 182°C. The entire process requires _____ cal. Round your answer to the nea

ICE Princess25 [194]

Answer:

12432 cal.

Explanation:

The process to change ice at -32 ºC to steam at 182 ºC can be divided into 5 steps:

1. Heat the ice to 0 ºC, which is the fusion temperature.

2. Melt the ice (obtaining liquid water), which is a process at constant pressure and temperature, so the liquid obtained is also at 0ºC.

3. Heat the liquid water from 0 ºC to 100 ºC, which is the vaporization normal temperature of the water.

4. Vaporization of all the water; this is also a process that occurs at constant pressure and temperature, so the produced steam will be at 100ºC.

5. Heat the steam from 100 ºC to 182 ºC.

Each process has a required energy, and the sum of the energy required for each and all of the steps is the total amount of energy required for the whole process:

$E_T=E_1+E_2+E_3+E_4+E_5$

$E_1$ is a heating process for the ice, so we know that the energy required is proportional to the temperature difference through the specific heat:

$E_1=m*Cp_{sol}*(T_2-T_1)\\E_1=16g*0.5\frac{cal}{gC}*(0-(-32))=256cal$

$E_2$ is a phase change process, so we do not use the specific heat (sensible heat), but the fusion heat (latent heat), so:

$E_{2}=m*dh_{f}={16g*80\frac{cal}{g}}=1280cal$

Analogously,

$E_3=m*Cp_{liq}*(T_3-T_2)=16g*1.00\frac{cal}{gC}*(100-0)C = 1600 cal$

$E_{4}=m*{dh_{vap}}\\\\E_4=16g*540\frac{cal}{g} =8640cal$

$E_{5}=m*Cp_{vap}*(T_{5}-T_{4})\\E_{5}={16g*0.5\frac{cal}{gK}*(182-100)K}=656cal$

Finally, the total energy required is:

$E_T=256cal+1280cal+1600cal+8640cal+656cal\\E_T=12432cal$

8 0

3 years ago

PLEASEEEEE HELP!!!!!!!!

Umnica [9.8K]

Gamma waves have the highest frequencies and shortest wavelengths

6 0

3 years ago

Suppose that the speed of a ball moving in a horizontal circle is increasing at a steady rate. Is this increase in speed produce

lana [24]

Answer:

No.

Explanation:

Centripetal acceleration would make the ball move towards the center of the circle. Centri- means "center", -petal means "towards". But since the ball has its own velocity that is perpendicular to the centripetal force vector, the centripetal acceleration can only change the direction of the velocity. Which means that centripetal acceleration cannot increase the ball's speed.

4 0

3 years ago

Read 2 more answers

Sobre uma caixa de massa 20 kg atuam duas forças de módulos constantes, F₁ = 15 N e F₂ = 20 N. Determine o módulo da aceleração

Aleks04 [339]

Answer:

If the two forces have the same direction, the acceleration = 1.75 m/s² (in the direction of the two forces).

If the two forces have opposite direction, the acceleration = 0.25 m/s² (in the direction of the larger of the two forces, the 20 N force).

Explanation:

English Translation

Two constant modulus forces act on a 20 kg mass box, F₁ = 15 N and F₂ = 20 N. Determine the acceleration module acquired by the body in the event that these forces have the same direction and opposite directions.

Solution

According to one of Newton's laws of motion, the resultant of the forces acting on a body is what causes the acceleration of that body.

Two forces, F₁ = 15 N and F₂ = 20 N, act on a 20 kg Mass box.

If the resultant of the forces acting on the mass is F, the resultant is related to the mass (m) and acceleration (a) of the body by

F = ma

If the two forces have the same direction, the resultant of the two forces acting on the mass is

F = F₁ + F₂ = 15 + 20 = 35 N

F = ma

35 = 20×a

a = (35/20) = 1.75 m/s² (in the direction of the two forces).

If the two forces have opposite direction, the resultant of the two forces acting on the mass is

F = F₂ - F₁ = 20 - 15 = 5 N

F = ma

5 = 20×a

a = (5/20) = 0.25 m/s² (in the direction of the larger of the two forces, the 20 N force).

Hope this Helps!!!

8 0

3 years ago

If forces acting on an object are unbalanced, the object could experience a change in ________.