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Paraphin [41]
3 years ago
5

A particle that has a mass of 5.0 kg is acted on by a force of 4.5 N. The acceleration of the particle is: a 0.9 m/s^2 b 1.1 m/s

^2 c. 2.9 m/s^2 d. 22.5 m/s^2
Physics
1 answer:
Gwar [14]3 years ago
6 0

Answer:

a) a = 0.9 m/s^2

Explanation:

As per Newton's 2nd law we know that net force on an object of mass "m" is given by the formula

F = ma

so net force is the product of mass and acceleration

here we know that

mass = 5 kg

net force on the particle is 4.5 N

so from above equation we have

4.5 = 5 \times a

so the acceleration is given as

a = \frac{4.5}{5} = 0.9 m/s^2

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Which car has the most kinetic energy?
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Answer:

B. A car of mass 2000 kg with speed 7 m/s

Explanation:

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where m is the mass of the object and v is its speed.

From the formula, we see that the larger the mass and the speed of the object, the larger its kinetic energy. Among the choices given, we see that the car with largest mass and largest speed is car B, which has a mass of 2000 kg and speed of 7 m/s. Its kinetic energy is:

K=\frac{1}{2}(2000 kg)(7 m/s)^2=49,000 J

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4 years ago
Causing a collision while speeding puts points on your license
Marizza181 [45]
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A solid cylinder is mounted above the ground with its axis of rotation oriented horizontally. A rope is wound around the cylinde
Romashka [77]

Answer:

(a)10.5 rad/s2

(b) 20.9 rev

(c) 47.27 m

Explanation:

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This solid cylinder would have a moment of inertia around it's rotating axis of:

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(a)We can use Newton's 2nd law to calculate the angular acceleration exerted by such torque on the solid cylinder

\alpha = \frac{To}{I} = \frac{187.17}{17.82} = 10.5 rad/s^2

(b) With such constant angular acceleration, the angle it would make after 5s is

\theta = \frac{\alphat^2}{2} = \frac{10.5*5^2}{2} = 131.3 rad

Since each revolution equals to 2\pi rad of angle, we can calculate the number of revolution it makes

\frac{\theta}{2\pi} = \frac{131.3}{6.28} \approx 20.9 rev

(c) Assume the thickness of the rope is negligible (and its wounded radius is unchanging), we can calculate the rope length unwinded after rotating 131.3rad

\theta R = 131.3*0.36 = 47.27 m

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3 years ago
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