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Paraphin [41]
3 years ago
5

A particle that has a mass of 5.0 kg is acted on by a force of 4.5 N. The acceleration of the particle is: a 0.9 m/s^2 b 1.1 m/s

^2 c. 2.9 m/s^2 d. 22.5 m/s^2
Physics
1 answer:
Gwar [14]3 years ago
6 0

Answer:

a) a = 0.9 m/s^2

Explanation:

As per Newton's 2nd law we know that net force on an object of mass "m" is given by the formula

F = ma

so net force is the product of mass and acceleration

here we know that

mass = 5 kg

net force on the particle is 4.5 N

so from above equation we have

4.5 = 5 \times a

so the acceleration is given as

a = \frac{4.5}{5} = 0.9 m/s^2

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If the voltage across a circuit element of constant resistance is doubled, how is the current through the circuit element affect
Karo-lina-s [1.5K]

Answer:

The current through the circuit element will also be doubled.

Explanation:

The relationship between voltage and current of a circuit element is given by Ohm's Law. According to Ohm's Law:

Voltage = (Resistance)(Current)

If the resistance of the element is kept constant, the relation between Voltage and Current through that element becomes as follows:

Voltage = (Constant)(Current)

Voltage α Current

Thus, the voltage is directly proportional to the current for constant value of the resistance.

Therefore, when the voltage across a circuit element of constant resistance is doubled, <u>the current through the circuit element will also be doubled.</u>

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Light travels at a constant speed of about 300,000 km/s. This speed is referred to as the speed of light. A light year is the di
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Based on the information in the question, a light year is the distance traveled light in one year. Then if the light from the star Centauri takes 4.2 years to reach the earth, then its distance from earth is 4.2 light years.

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Ben and Dan both weigh 600 N. They are doing pull-ups together. Each pull-up is 0.5 meters of distance. How much work do they ea
Natasha2012 [34]

Answer:

300 J

Explanation:

Work = (Force)*(distance) = 600 N ∗ 0.5 m = 300 J

5 0
2 years ago
There is a current of 0.83 A through a lightbulb in a 120 V circuit. What is the resistance of this lightbulb?
Lemur [1.5K]

Considering the Ohm's law, the resistance of the lightbulb is 144.58 Ω.

<h3>Definition of current</h3>

The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.

<h3>Definition of voltage</h3>

The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.

<h3>Definition of resistance</h3>

Resistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).

<h3>Ohm's law</h3>

Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.

This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.

Mathematically, Ohm's law is expressed as:

I=\frac{V}{R}

Where:

  • I is the current measured in amps (A).
  • V the voltage measured in volts (V).
  • R the resistance that is measured in ohms (Ω).

<h3>Resistance of the lightbulb</h3>

In this case, you know that the voltage between two points in a circuit is 120 V and there is a current of 0.83 A.

Replacing in the Ohm's Law:

0.83A=\frac{120 V}{R}

Solving:

0.83 A× R=  120 V

R=\frac{120 V}{0.83A}

<u><em>R= 144.58 Ω</em></u>

Finally, the resistance of the lightbulb is 144.58 Ω.

Learn more about Ohm's law:

brainly.com/question/13076023

brainly.com/question/17286882

brainly.com/question/2275770

#SPJ1

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2 years ago
During an experiment, Ellie records a measurement of 0.0034 m. How would
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Answer:

(A)   She needs to move the decimal point by 3 places

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3 years ago
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