Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Answer:
if sin (x-3) degrees = cos (2x+6) degrees, find the value of x.
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Note: sin and cos are complementary functions....
sin(x) = cos (90-x)
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Your Problem:
sin(x-3) = cos(90-(x-3))
Equation:
90-[x-3] = 2x+6
90-x+3 = 2x+6
3x = 93-6
x = 31-2
x = 29
Step-by-step explanation:
Find the Distance Between Two Points
Use the distance formula to determine the distance between two points.
Exact Form:
√85
Decimal Form:
9.21954445
…
Answer:
I know it.
Step-by-step explanation:
triangles always add up to 180 degrees so add 43 and 32 together and you will get 75 so then you take 75 off 180 and you will get 105
that's your answer
A = 105
Answer:
m=0
Step-by-step explanation:
<em><u>mx²+2x-1=0</u></em>
if x=1/2 then
m(1/2)² +2(1/2)-1=0
m/4+1-1=0
m/4=0
m=0
