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4 years ago

Name the principal on which a rocket works

Physics

1 answer:

Andre45 [30]4 years ago

5 0

The rocket works on the principal of action and reaction. Newton's third law of motion.

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Two large parallel metal plates carry opposite charges. They are separated by 0.20 m and the p.d. between them is 500 V. What is

Bezzdna [24]

Hi there!

We can use the following relationship between the Potential Difference and the Electric field:

$V = E d$

V = Potential Difference (500V)
E = Electric Field (V/m)
d = separation between plates (0.2 m)

We can rearrange the equation to solve for the electric field:
$E = \frac{V}{d}\\\\$

Plug in the given values.

$E = \frac{500}{0.2} = \boxed{2500 \frac{V}{m}}$

3 0

2 years ago

What is meant by the phrase "a consistent method of measurement"?

julia-pushkina [17]

A measurement that will always give the same answer.

5 0

3 years ago

For anyone taking the Velocity and Acceleration Quick Check, Here are the answer.s!

Kipish [7]

Answer:

this is 100% correct

Explanation:

5 0

3 years ago

A circuit consists of a resistance R, and an inductance L in parallel connected, which is in series with a second resistance R2.

Allisa [31]

Answer:

The impedance of the inductor is ω L:

This is in parallel wth R giving a resistance of the parallel combination:

1 / Rp = 1 / ω L + 1 / R

Rp = (ω L * R) / (ω L + R) for the impedance of the parallel combination

Total resistance (impedance) Rt = Rp + R2 = Z

One can use the term impedance to show that the resulting current is not in phase with the resulting voltage

phase angle φ - cos φ = ω L / Rt

V = I Z shows the relation of voltage and urrent

5 0

2 years ago

The cart now moves toward the right with an acceleration toward the right of 2.50 m/s2. What does spring scale Fz read? Show you

katrin2010 [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The spring scale $F_2$ reads $F_2 = 2.4225 \ N$

Explanation:

From the question we are told that

The first force is $F_1 = 10.5 \ N$

The acceleration by which the cart moves to the right is $a = 2.50 \ m/s^2$

The mass of the cart is m = 3.231 kg

Generally the net force on the cart is

$F_{net} = F_1 - F_2$

This net force is mathematically represented as

$F_{net} = m * a$

$m* a = 10 - F_2$

$F_2 = 10.5 - 2.5 (3.231)$

$F_2 = 2.4225 \ N$

3 0

3 years ago