Answer : ![a=10\ m/s^2](https://tex.z-dn.net/?f=a%3D10%5C%20m%2Fs%5E2)
Explanation :
It is given that,
Mass of the engine, m = 30 kg
Thrust is equivalent to the force acting perpendicularly and it is F = 300 N
According to Newton's second law of motion :
![F = m\times a](https://tex.z-dn.net/?f=F%20%3D%20m%5Ctimes%20a)
a is the acceleration of the engine.
![a=\dfrac{F}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BF%7D%7Bm%7D)
![a=\dfrac{300\ N}{30\ Kg}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B300%5C%20N%7D%7B30%5C%20Kg%7D)
![a=10\ m/s^2](https://tex.z-dn.net/?f=a%3D10%5C%20m%2Fs%5E2)
So, the acceleration of the engine is
.
Hence, this is the required solution.
Answer:
Troposphere
High-pressure areas form due to downward motion through the troposphere, the atmospheric layer where weather occurs.
Answer: D. An action-reaction force pair
Explanation: When you sit in your chair, your body exerts a downward force on the chair and the chair exerts an upward force on your body. There are two forces resulting from this interaction - a force on the chair and a force on your body. Another example would be a person pushing against a wall (action force), and the wall exerts an equal and opposite force against the person.
Answer with Explanation:
We are given that
Angle of incidence,![i=30^{\circ}](https://tex.z-dn.net/?f=i%3D30%5E%7B%5Ccirc%7D)
Angle of refraction,![r=19.24^{\circ}](https://tex.z-dn.net/?f=r%3D19.24%5E%7B%5Ccirc%7D)
a.Refractive index of air,![n_1=1](https://tex.z-dn.net/?f=n_1%3D1)
We know that
![n_2sinr=n_1sini](https://tex.z-dn.net/?f=n_2sinr%3Dn_1sini)
![n_2=\frac{n_1sin i}{sin r}=\frac{sin30}{sin19.24}=1.517](https://tex.z-dn.net/?f=n_2%3D%5Cfrac%7Bn_1sin%20i%7D%7Bsin%20r%7D%3D%5Cfrac%7Bsin30%7D%7Bsin19.24%7D%3D1.517)
b.Wavelength of red light in vacuum,![\lambda=632.8nm=632.8\times 10^{-9} m](https://tex.z-dn.net/?f=%5Clambda%3D632.8nm%3D632.8%5Ctimes%2010%5E%7B-9%7D%20m)
![1nm=10^{-9} m](https://tex.z-dn.net/?f=1nm%3D10%5E%7B-9%7D%20m)
Wavelength in the solution,![\lambda'=\frac{\lambda}{n_2}](https://tex.z-dn.net/?f=%5Clambda%27%3D%5Cfrac%7B%5Clambda%7D%7Bn_2%7D)
![\lambda'=\frac{632.8}{1.517}=417nm](https://tex.z-dn.net/?f=%5Clambda%27%3D%5Cfrac%7B632.8%7D%7B1.517%7D%3D417nm)
c.Frequency does not change .It remains same in vacuum and solution.
Frequency,![\nu=\frac{c}{\lamda}=\frac{3\times 10^8}{632.8\times 10^{-9}}](https://tex.z-dn.net/?f=%5Cnu%3D%5Cfrac%7Bc%7D%7B%5Clamda%7D%3D%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B632.8%5Ctimes%2010%5E%7B-9%7D%7D)
Where ![c=3\times 10^8 m/s](https://tex.z-dn.net/?f=c%3D3%5Ctimes%2010%5E8%20m%2Fs)
Frequency,![\nu=4.74\times 10^{14}Hz](https://tex.z-dn.net/?f=%5Cnu%3D4.74%5Ctimes%2010%5E%7B14%7DHz)
d.Speed in the solution,![v=\frac{c}{n_2}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bc%7D%7Bn_2%7D)
![v=\frac{3\times 10^8}{1.517}=1.98\times 10^8m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B1.517%7D%3D1.98%5Ctimes%2010%5E8m%2Fs)
Answer:
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Explanation:
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