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3 years ago

14

An atom with two protons, three neutrons and two electrons would have a mass of about how many atomic mass units?

1 answer:

Katarina [22]3 years ago

8 0

The answer is 5 amu.

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When I double displacement reaction takes place, one of the products must be_______.

sattari [20]

Answer:

the answer would be Salt

Explanation:

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3 years ago

Read 2 more answers

A meter stick is held vertically above your hand, with the lower end between your thumb and first finger. On seeing the meter st

inessss [21]

Answer:

$t=0.193s$

Explanation:

What is said is that the meter fell d=18.3cm=0.183m under the action of gravity. We can use the formula for accelerated motion:

$d=v_0t+\frac{at^2}{2}$

Since it departed from rest it will mean that:

$d=\frac{at^2}{2}$

So our time will be:

$t=\sqrt{\frac{2d}{a}}$

Which for our values is:

$t=\sqrt{\frac{2(0.183m)}{(9.81m/s^2)}}=0.193s$

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3 years ago

Find the frequency if the period is 15 us.

Sav [38]

Answer:

The frequency is $0.667$ × $10^{6}$ $Hz$ .

Explanation:

Period is defined as the time taken by any element to attempt one complete oscillatory motion in one second.
Frequency is the number of complete oscillations made in one second.

Frequency and period are inversely proportional to each other.

In mathematical term: $frequency$ = $\frac{1}{period}$ .
As we are given, $period$ = $15$ × $10^{-6}$ $s$ .
We can easily calculate frequency as: $f\\$ = $\frac{1}{15. 10^{-6} }$
So frequency is $f$ = $0.667$ × $10^{6}$ $Hz$ .

6 0

3 years ago

When you compare the prices of two different pairs of shoes, money is a _____.

Mashcka [7]

Answer:

c

Explanation:

3 0

3 years ago

g power output of 87 W. At what distance will the decibel reading be 120 dB, which is noise level of a loud indoor rock concert

Kazeer [188]

Given that,

Output power = 87 W

Decibel reading = 120 dB

We need to calculate the intensity of sound

Using formula of intensity of sound

$dB=10\log(\dfrac{I}{I_{0}})$

Put the value into the formula

$120=10\log(\dfrac{I}{1\times10^{-12}})$

$12=log(\dfrac{I}{1\times10^{-12}})$

$10^{12}=\dfrac{I}{1\times10^{-12}}$

$I=10^{12}\times1\times10^{-12}$

$I=1\ W/m^2$

We need to calculate the distance

Using relation of power out[ut and intensity

$I=\dfrac{P}{4\pi r^2}$

Put the value into the formula

$1=\dfrac{87}{4\pi r^2}$

$r=\sqrt{\dfrac{87}{4\pi}}$

$r=2.63\ m$

Hence, The distance is 2.63 m

7 0

3 years ago