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Dmitry [639]
3 years ago
7

Which element would you expect to have a higher mass cadmium or zinc

Chemistry
2 answers:
swat323 years ago
8 0

Answer:

ZINC

Explanation:

Zinc is a chemical element with the symbol Zn and atomic number 30. Zinc is a slightly brittle metal at room temperature and has a silvery-greyish appearance when oxidation is removed. It is the first element in group 12 of the periodic table.

Hope it helps

Sliva [168]3 years ago
3 0
Answer is Cadmium


Atomic masses of Cadium & Zinc

112.411 u
Cadmium/Atomic mass

65.38 u
Zinc/Atomic mass
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Which of these molecules is nonpolar?<br> a.CH3CI<br> b.CO<br> c.O2<br> d.PF3
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Which reaction represents the process of neutralization? Mg(s)+2HCl(aq) MgCl 2 (aq)+H 2 (g) HCl(aq)+KOH(aq) KCl(aq)+H 2 O(l) C.
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Answer:

HCl(aq) + KOH(aq) --> KCl(aq) + H2O(l)

Explanation:

A neutralization reaction is the process between an acid and a base (there are a number of different ways to define acids and bases). An acid is a compound, which dissolves in water by releasing H+ ions, and a base is a compound, which dissolves in water by releasing OH- ions (by Arrhenius' definition, the simplest one). In this case, the neutralization reaction is the process between HCl (hydrochloric acid) - an acid, and KOH (potassium hydroxide) - a base.

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Describe the changed that happened in the crayon and candle when they cooled after 3 to 5 minutes.​
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3 years ago
I need part 1 and 2 please , just separate answers
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First, we have to remember the molarity formula:

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Part 1:

In this case, our solute is sodium nitrate (NaNO3), and we have the mass dissolved in water, then we have to convert grams to moles. For that, we need the molecular weight:

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Now, we have the necessary data to calculate the molarity (with the solution volume of 200 mL):

M=\frac{0.04678\text{ mol}}{200\text{ mL*}\frac{1\text{ L}}{1000\text{ mL}}}=\text{ 0.2339 M}

The molarity of this solution equals 0.2339 M.

Part 2:

In this case, we have the same amount (in moles and mass) of sodium nitrate, but a different volume of solution, then we only have to change it:

M=\text{ }\frac{0.04678\text{ mol}}{275\text{ mL *}\frac{1\text{ L}}{1000\text{ mL}}}=\text{ 0.1701 M}

So, the molarity of this solution is 0.1701 M.

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