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Dmitry [639]
3 years ago
7

Which element would you expect to have a higher mass cadmium or zinc

Chemistry
2 answers:
swat323 years ago
8 0

Answer:

ZINC

Explanation:

Zinc is a chemical element with the symbol Zn and atomic number 30. Zinc is a slightly brittle metal at room temperature and has a silvery-greyish appearance when oxidation is removed. It is the first element in group 12 of the periodic table.

Hope it helps

Sliva [168]3 years ago
3 0
Answer is Cadmium


Atomic masses of Cadium & Zinc

112.411 u
Cadmium/Atomic mass

65.38 u
Zinc/Atomic mass
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i need a picture to solve

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Hypoventilation can cause oxygen levels to fall too low, a condition called . carbon dioxide levels may rise too high, a conditi
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1 year ago
What is another word for the dependent variable?
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2 years ago
For doping silicon with boron, silicon specimen was kept in gaseous atmosphere containing B2O3 that maintained the B concentrati
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Solution :

From Fick's law:

$\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=N_a$

Mass balance: Exits = Accumulation

-N_A A = \frac{dm}{dt}

-N_A A = \frac{dVp}{dt}

-N_A A = \frac{dV}{dt}p

-N_A A = \frac{dhA}{dt}

-N_A A = \frac{dh}{dt} \times Ap

From the last step, area cancels out and thus leaves :

-N_A  = \frac{dh}{dt} \times p

So now we can substitute the $N_A$ by the Fick's law

$\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=\frac{dh}{dt} p$

Substituting the values we get

$=\frac{-4 \times 10^{-13}}{0.0001} \times (3 \times 10^{26} - C_{A2}) = \frac{dh}{dt} \times 2.46$

$=-4 \times 10^{-9} \times( 3 \times 10^{26} - C_{A2}) = 0.0001 \times 2.46$

$= -7800 \times 4 \times 10^{-9}  \times (3 \times 10^{26}-C_{A2})=0.000246$$=-(3 \times 10^{26}-C_{A2}) = 7.8846 \times 100 \times \frac{1}{69.62} \times 6.022 \times 10^{23}$

$C_{A2} = 6.85 \times 10^{28} \ \text{ boron atoms} /m^3$

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