Answer:
hope this help by the way found off of yahoo
Explanation:
Calculate the number of grams of nitrogen dioxide that are produced from
4 moles of nitric oxide.
2NO(g) + O2(g) -->2NO2(g)
I really need help with this... I need to know how to work it too... I can balance it out but not sure about grams... This is it balanced out with 4 moles of nitric oxide
4NO(g) + 2O2(g) ->4NO2(g) please help and explain i want to learn this
Answer:
1. 43.44g of HCl
2. 26.67 L of HCl
Explanation:
1) Molarity of a solution = number of moles (n) ÷ Volume (V)
According to the provided information in this question,
V = 350 mL = 350/1000 = 0.350L
Molarity = 3.4 M
Using Molarity = n/V
3.4 = n/0.350
n = 3.4 × 0.350
n = 1.19mol
Using the formula below to calculate the mass of HCl;
mole = mass/molar mass
Molar mass of HCl = 1 + 35.5 = 36.5g/mol
mole = mass/MM
mass = 1.19 mol × 36.5g/mol
mass = 43.44g of HCl
2) At STP, HCl has a pressure of 1atm, a temperature of 273K
V = ?
n = 1.19 mol
R = 0.0821 Latm/molK
Using PV = nRT
V = nRT/P
V = 1.19 × 0.0821 × 273/1
Volume = 26.67L
Answer:
c. benzoic acid
Explanation:
The given reaction is an example of a Grignard reaction:
When chlorobenzene (C₆H₅Cl) reacts with Mg in ether, an intermediate is formed (C₆H₅MgCl).
Said intermediate then reacts with CO₂ producing a benzoic acid salt (C₆H₅CO₂X), this salt is then neutralized with dilute HCl producing benzoic acid (C₆H₅CO₂H).
<span>The Ionization energy decreases because the full s orbital shields the electron entering the p orbital. This is known as "shielding", When each new electron experiences attraction from the nucleus and repulsion forces from the S orbitals, the net force on outer shell electrons is significantly smaller. Therefore, ionization energy decreases during these groups.</span>
The 2-bromo-1-chloro-2-methylpropane molecule contains a total of 14 atom(s). There are 4 Carbon atom(s), 8 Hydrogen atom(s), 1 Chlorine atom(s) and 1 Bromine atom(s). A chemical formula of 2-bromo-1-chloro-2-methylpropane can therefore be written as C4H8BrCl. Is it also commonly called as Propane.
