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Ymorist [56]
3 years ago
9

Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive

object; the ring has a diameter of about 16 light-years and an orbital speed of about 130 km/s. For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Black hole calculations.
Determine the mass M of the massive object at the center of the Milky Way galaxy.Take the distance of one light year to be 9.461 x 1015m.Express your answer in kilograms.
Physics
1 answer:
Burka [1]3 years ago
4 0

Answer:

1.91773\times 10^{37}\ kg

Explanation:

v = Orbital speed = 130 km/s

d = Diameter = 16 ly

r = Radius = \dfrac{d}{2}=\dfrac{16}{2}=8\ ly

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

1\ ly=9.461\times 10^{15}\ m

As the centripetal force balances the gravitational energy we have the following relation

\dfrac{GMm}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow M=\dfrac{v^2r}{G}\\\Rightarrow M=\dfrac{130000^2\times 8\times 9.461\times 10^{15}}{6.67\times 10^{-11}}\\\Rightarrow M=1.91773\times 10^{37}\ kg

Mass of the the massive object at the center of the Milky Way galaxy is 1.91773\times 10^{37}\ kg

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The final answer is 1,200 m.

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3 years ago
Which statement is true about a falling object? (Assume no
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2 years ago
The force between a pair of .005 charges is 750 N. What is the distance between them?
Ganezh [65]

Question: The force between a pair of 0.005 C is 750 N. What is the distance between them?

Answer:

17.32 m

Explanation:

From coulomb's Law,

F = kqq'/r²........................... Equation 1

Where F = Force between the force, q' and q = both charges respectively, k = coulomb's constant, r = distance between both charges.

make r the subject of the equation above

r = √(kqq'/F)..................... Equation 2

From the question,

Given: q = q' = 0.005 C, F = 750 N

Constant: k = 9.0×10⁹ Nm²/C².

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r = √(9.0×10⁹×0.005×0.005/750)

r = √(300)

r = 17.32 m.

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in which of the exercise and sports science do specialist study achievement motivation , arousal attribution and personality dev
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Sport and exercise psychology

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Here you study the psychological factors that  are connected to your performance and contribution to sport, exercises and physical activities.Through application of psychological principles you can attain higher mental health  and your performance will be enhanced. For example, you will be able to recognize times when you experience emotional states without without knowing the reasons or causes which is a concept of arousal attribution.Understanding your pattern of behavior and attitude builds up your personality making you distinctive.

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7 0
3 years ago
An object is placed to the left of a convex mirror, such that the object-to-image distance is 140 cm.
labwork [276]

Answer:

The focal length of the mirror is 52.5 cm.

Explanation:

Given that,

Object to Image distance d = 140 cm

Image distance v= 35 cm

We need to calculate the object distance

u = d-v

u = 140-35=105\ cm

We need to calculate the focal length

Using formula of mirror

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-105}+\dfrac{1}{35}

\dfrac{1}{f}=\dfrac{2}{105}

f=52.5\ cm

Hence, The focal length of the mirror is 52.5 cm.

6 0
3 years ago
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