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3 years ago

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Gas a bG1 5.22 0.0289G2 1.05 0.0388G3 2.31 0.0467G4 4.05 0.0310Based on the given van der Waals constants for four hypothetical

gases (G1, G2, G3, G4), arrange these hypothetical gases in order of decreasing strength of intermolecular forces. Assume that the gases have similar molar masses.Rank from strongest to weakest intermolecular attraction. To rank items as equivalent, overlap them.Gas 3, Gas 2, Gas 1, Gas 4

1 answer:

inysia [295]3 years ago

3 0

Answer:

Gas 2, Gas 3, Gas 4, Gas 5 is the order of decreasing strength of inter-molecular forces.

Explanation:

The strength increases as there is a decrease in the vanderwaals constant and vice versa.

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To solve this problem we will use the linear motion description kinematic equations. We will proceed to analyze the general case by which the analysis is taken for the second car and the tenth. So we have to:

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Where,

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$2L \frac{1}{2} at_2^2$

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When the tenth car has passed the length will be 10 times the initial therefore:

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From the relationship when the car has passed and the time difference we will have to:

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$t_2= (\frac{5\sqrt{2}}{\sqrt{2}-1})^2$

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$\frac{L}{a} = \frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2$

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$18 \frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2 = t_3^2$

$t_3 = 36.213s$

The time when you have passed it would be:

$20\frac{1}{4} (\frac{5\sqrt{2}}{\sqrt{2}-1})^2 = t_4^2$

$t_4 = 38.172$

The difference between the two times would be:

$t_4-t_3 = 38.172-36.213 \approx 2s$

Therefore the correct answer is C.

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3 years ago

Balance the following chemical equation:<br> CO2 + VH20 - CH1206+ voz<br> [<br> ~<br> CO₂+

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Answer:

Explanation:

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3 years ago

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Pavel [41]

Answer:

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3 years ago