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MakcuM [25]
4 years ago
9

What is the first step in solving the inequality 2x + 3 ≥ 17?Divide the left side by 2.Subtract 3 from both sides.Change the dir

ection of the inequality.Change the inequality to >.
Mathematics
1 answer:
Wewaii [24]4 years ago
4 0

Answer:

Subtract 3 from both sides.

Step-by-step explanation:

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SOMEONE please help!!
Paul [167]
So you are given a recursive series, which is an equation that writes itself. Now we want to create a explicit rule. Explicit rule is a pattern that uses our first term and add our common difference. So it gives us our first term. a_{1}  = -3

Lets find the second term of the recursive series. 

a_2 = -3 +7 = 4

So it is increasing by 7

So our explicit rule is:

a_n = -3 + 7(n-1)
8 0
3 years ago
What is the measure of x
Ivahew [28]

Answer:

56.25°

Step-by-step explanation:

cos x° = b/h = 15/27 = 5/9

x° = cos^(-1) (5/9) = 56.25°

7 0
3 years ago
How do you simplify these expressions
Oxana [17]
Answer is given above

4 0
4 years ago
Find THE LENGTH I WILL MWKE YOU ANSWER THE BRAINLIEST
Goshia [24]

Answer:

i think the awnser is d

Step-by-step explanation:

i counted 13

4 0
3 years ago
assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28
melomori [17]

Given:

x and y are both differentiable functions of t.

4x^2+3y^3=28

x=-1\text{ and }\dfrac{dy}{dt}=8

To find:

The value of \dfrac{dx}{dt}.

Solution:

We have,

4x^2+3y^3=28       ...(i)

At x=-1,

4(-1)^2+3y^3=28

4+3y^3=28

3y^3=28-4

3y^3=24

Divide both sides by 3.

y^3=8

Taking cube root on both sides.

y=2

So, y=2 at x=-1.

Differentiate (i) with respect to t.

4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0

Putting x=-1, y=2 and \dfrac{dy}{dt}=8, we get

4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0

-8\dfrac{dx}{dt}+9(4)(8)=0

-8(\dfrac{dx}{dt}-9(4))=0

Divide both sides by -8.

\dfrac{dx}{dt}-36=0

\dfrac{dx}{dt}=36

Therefore, the value of 4x^2+3y^3=28 is 36.

6 0
3 years ago
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