Answer:
See explanations below
Explanation:
Power = Workdone/Time
Power of washer = 450watts
Time used to clean the clothes = 1hour = 3600secs
Energy used to clean a load of clothes in 1 hour of
washing = 450/3600
Energy used to clean a load of clothes in 1 hour of
washing = 0.125Joules
For drying;
Energy = 3000/1.5*3600
Energy = 3000/5400
Energy = 0.556Joules
Hence the energy in washing id 0.556Joules
Answer:
a = 4.9(1 - sinθ - 0.4cosθ)
Explanation:
Really not possible without a complete setup.
I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g
F = ma
mg - mgsinθ - μmgcosθ = (m + m)a
mg(1 - sinθ - μcosθ) = 2ma
½g(1 - sinθ - μcosθ) = a
maximum acceleration is about 2.94 m/s² when θ = 0
acceleration will be zero when θ is greater than about 46.4°
Answer:
<u>We are given: </u>
initial velocity (u) = 0 m/s
final velocity (v) = 10 m/s
displacement (s) = 20 m
acceleration (a) = a m/s/s
<u>Solving for 'a'</u>
From the third equation of motion:
v² - u² = 2as
replacing the variables
(10)² - (0)² = 2(a)(20)
100 = 40a
a = 100 / 40
a = 2.5 m/s²
if i am changing velocity, i must also have <u>acceleration</u> and a net <u>force</u>
<h2>
<u>Newton's</u><u> </u><u>first</u><u> </u><u>law</u><u> </u><u>of</u><u> </u><u>motio</u><u>n</u></h2>
- Newton's first law of motion states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
According to Newton's first law of motion, without a force acting on an object, its velocity does not change. The net force acts on an object to change its velocity and cause acceleration.
Read more about velocity:
brainly.com/question/4931057
Answer
given,
discharge rate from pipe = 1000 gallons/minutes
now,
flow rate in cubic meters per second
1 gallon = 0.00378541 m³
1 min = 60 s
Q = 
Q = 0.063 m³/s
flow rate in liters per minute
1 gallon = 3.78541 L
Q = 
Q = 3785.41 m³/min
flow rate in cubic feet per second
1 gallon = 0.133681 ft³
1 min = 60 s
Q = 
Q = 2.23 ft³/s