To solve this exercise we need the concept of Kinetic Energy and its respective change: Initial and final kinetic energy.
Let's start considering that the angular velocity is given by,

Where,
V = linear speed
R = the radius
In the case of the initial kinetic energy:

Where I is the moment of inertia previously defined.

In the case of the final kinetic energy, we have to,


For conservation of Energy we have, that
, then (canceling the mass and the radius)





Answer:
<em><u>TROPOSPHERE</u></em><em><u> </u></em><em>the</em><em> </em><em>lowest</em><em> </em><em>layer</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>atmosphere</em><em> </em><em>closest</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>earth</em>
<em><u>STRATOSPHERE</u></em><em><u> </u></em><em>constant</em><em> </em><em>temperature</em><em> </em>
<em>MESOSPHERE</em><em> </em><em>layer</em><em> </em><em>with</em><em> </em><em>the</em><em> </em><em>strongest</em><em> </em><em>wind</em><em> </em><em>and</em><em> </em><em>below</em><em> </em><em>the</em><em> </em><em>themosphere</em>
<em><u>Themosphere</u></em><em><u> </u></em><em>a</em><em>bsorbs</em><em> </em><em>UV</em><em> </em><em>radiation</em><em> </em>
Power = Work/Time
Convert 5 min to seconds and divide 2150J by that number.
An upwards acceleration of the elevator would cause this greater reading since the scale displays the Normal Force of the object on it. The inertia of the person would prefer to stay stationary, so the scale must push up on the person to accelerate him upward along with the elevator. This results in the following equation:
W = mg + ma
Where mg represents the weight reading without external acceleration and ma as the weight reading due to the external acceleration.
Answer:
The answer is C-Spin a magnet around the wire on the piece of iron. Hope that helps :)