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Dima020 [189]
3 years ago
12

How many grams of NaF form when 0.589 mol of HF react with excess Na2SiO3?

Chemistry
1 answer:
BartSMP [9]3 years ago
8 0

Answer:

6.18 g

Explanation:

We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                                             41.99  

                 Na₂SiO₃ + 8HF ⟶ 2NaF + H₂SiF₆ + 3H₂O  

<em>n</em>/mol:                         0.58    

1. Use the molar ratio of NaF:HF to calculate the moles of NaF.

\text{Moles of NaF} = \text{0.589 mol HF} \times \frac{\text{2 mol NaF}}{\text{8 mol HF}} = \text{0.1472 mol NaF}

2. Use the molar mass of NaF to calculate the mass of NaF.

\text{Mass of NaF} = \text{0.1472 mol NaF} \times \frac{\text{41.99 g NaF}}{\text{1 mol NaF}} = \text{6.18 g NaF}

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Bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter
Alisiya [41]

Answer:Hence, the bond length in HCl is 125 pm.

Explanation:

Bond length : It is an average distance between the nuclei of two bonded atoms in a molecule.

Also given that bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter-nuclear distance between the two atoms when the potential energy of the system reaches its lowest value. Beyond this if atoms come closer to each other then their will be repulsion between them.

So, the bond length between the Hydrogen and Chlorine atom in HCl molecule is :

Bond length=radius _{hydrogen}+radius_{chlorine}=25pm+100pm=125pm

Hence, the bond length in HCl is 125 pm.

5 0
3 years ago
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Sladkaya [172]

Answer:

Explanation:

5 0
3 years ago
What is the concentration of kl solution if 20.68g of solute was added to enough water to form 100ml solution?
rewona [7]

Answer:

1.25 M

Explanation:

Step 1: Given data

Mass of KI (solute): 20.68 g

Volume of the solution: 100 mL (0.100 L)

Step 2: Calculate the moles of solute

The molar mass of KI is 166.00 g/mol.

20.68 g × 1 mol/166.00 g = 0.1246 mol

Step 3: Calculate the molar concentration of KI

Molarity is equal to the moles of solute divided by the liters of solution.

M = 0.1246 mol/0.100 L= 1.25 M

5 0
3 years ago
A first order reaction has 1/16 of the original amount left after 500 seconds. What is the half-life of the reactant in this rea
jonny [76]

A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.

<h3>What is a first order reaction?</h3>

It is a chemical reaction in which the rate of reaction is directly proportional to the concentration of the reacting substance.

First, we will calculate the rate constant using the following expression.

ln ([A]/[A]₀) = - k × t

ln (1/16[A]₀/[A]₀) = - k × 500 s

k = 5.55 × 10⁻³ s⁻¹

where,

  • [A] is the final concentration of the reactant.
  • [A]₀ is the initial concentration of the reactant.
  • k is the rate constant.
  • t is the elapsed time.

Next, we can calculate the half-life (th) using the following expression.

th = ln 2 / k = ln 2 / (5.55 × 10⁻³ s⁻¹) = 125 s

A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.

Learn more about first order reactions here: brainly.com/question/518682

5 0
2 years ago
Un atleta se dirige hacia la línea de salida a 6 m/s. Cuando pasa por la marca de 100 m, ponemos el cronómetro en marcha. Escrib
Romashka [77]

Answer:

Los parámetros dados del movimiento son;

La velocidad con la que el atleta se dirige hacia la línea de salida = 6 m / s

El punto en el que se inicia el cronómetro = marca de 100 m

La ecuación para la distancia recorrida, 's', se da como sigue;

s = 6 m / s × t

La distancia total recorrida, d = 100 + s

∴ d = 100 + 6·t

Los gráficos de las ecuaciones se crean con Microsoft Excel y se presentan de la siguiente manera;

Explanation:

4 0
3 years ago
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