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kvv77 [185]
3 years ago
5

Kepler deduced this law of motion from observations of Mars. What information confirms his conclusion that the orbit of Mars is

elliptical?
Physics
1 answer:
Leno4ka [110]3 years ago
6 0

Kepler noticed an imaginary line drawn from a planet to the Sun and this line swept out an equal area of space in equal times, If we then draw a triangle out from the Sun to a planet’s position at one point in time, it is notice that the area doesn't change even after the planet has left the original position say like after 2 to 3days or 2hours. So to have same area of triangle means that the the planet move faster when that are closer to the sun and slowly when they are far from the sun.

This led to Kepler's law of orbital motion.

First Law: Planetary orbits are elliptical with the sun at a focus.

Second Law: The radius vector from the sun to a planet sweeps equal areas in equal times.

Third Law: The ratio of the square of the period of revolution and the cube of the ellipse semi-major axis is the same for all planets.

It is this Kepler's law that makes Newton to come up with his own laws on how planet moves the way they do.

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A stationary boat in the ocean is experiencing waves from a storm. The waves move at 59 km/h and have a wavelength of 145 m . Th
krek1111 [17]

Answer:

The time elapses until the boat is first at the trough of a wave is 4.46 seconds.

Explanation:

Speed of the wave, v = 59 km/h = 16.38 m/s

Wavelength of the wave, \lambda=145\ m

If f is the frequency of the wave. The frequency of a wave is given by :

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{16.38\ m/s}{145\ m}\\\\f=0.112\ Hz

The time period of the wave is given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.112\ Hz}\\\\T=8.92\ s

We need to find the time elapses until the boat is first at the trough of a wave. So, the time will be half of the time period of the wave.

T=\dfrac{8.92}{2}\\\\T=4.46\ s

Hence, this is the required solution.

5 0
3 years ago
A 29 foot ladder leans against a building so that the angle between the ground and the ladder is 75 ∘ . How high does the ladder
Aloiza [94]

Answer:

28.01m

Explanation:

Opp/Hyp = Sin

Sin 75 = x/29

x = 29 sin 75

x = 28.01m

3 0
3 years ago
If a wave has speed of 235 m/s with a wavelength of 3 m, what is the frequency of the wave?
maria [59]
I think it’s 25 but I don’t know
5 0
2 years ago
A hammer of mass m falls from rest off of a roof and drops a height H onto your head.
belka [17]
For conservation of energy we have to:
 mgH=mv²/2 
 Clearing
<span> v=sqrt(2gH)
 Then, by definition 
</span><span> F=Δp/Δt= Δ(mv)/ Δt=m Δ(v)/Δt= 
</span> =m[sqrt(2gH)-0]/Δt= m[sqrt(2gH)]/ Δt
 the answer is
 F=m[sqrt(2gH)]/ Δt
 
6 0
3 years ago
For an object that travels at a fixed speed along a circular path, the acceleration of the object is
lidiya [134]
For an object that travels at a fixed speed along a circular path, the acceleration of the object is LARGER IN MAGNITUDE THE SMALLER THE RADIUS OF CIRCLE.
8 0
3 years ago
Read 2 more answers
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