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3 years ago

8

Which of these has the most inertia?

1 answer:

VashaNatasha [74]3 years ago

3 0

Answer:

A. a parked bus

Explanation:

Because a parked bus probably has the most mass out of these 4 and as we know, mass is that quantity that is solely dependent upon the inertia of an object. The more inertia that an object has, the more mass that it has. A more massive object has a greater tendency to resist changes in its state of motion.

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Suppose one night the radius of the earth doubled but its mass stayed the same. What would be an approximate new value for the f

Alex17521 [72]

Answer:

g' = g/4

Explanation:

The value of the free-fall acceleration at the surface of the earth, can be obtained applying Newton's 2nd law, assuming that the only force acting on an object at the surface of the earth, is the one produced by the mass of the Earth, i.e. gravity.
This force can be expressed according the Newton's Universal Law of Gravitation , as follows:

$F_{g} = G*\frac{m_{x} *m_{E} }{r_{E}^{2} } (1)$

From Newton's 2nd Law, we have:
$F = m* a (2)$
Since the left sides in (1) and (2) are equal each other, both right sides must be equal each other also.
Simplifying the mass m, we can write the acceleration a in (2) as the acceleration due to gravity, g, as follows:

$g = G*\frac{m_{E} }{r_{E}^{2} } (3)$

Since G is an universal constant, and the mass mE remains constant, if we double the radius of the Earth, the new value for the acceleration due to gravity (let's call it g'), is as follows:

$g' = G*\frac{m_{E} }{(2r_{E})^{2} } =G*\frac{m_{E} }{4*r_{E}^{2} } = g*\frac{1}{4} =\frac{g}{4} (4)$

4 0

3 years ago

Isaac walks 4 blocks north. Then he turns around and walks 1 block south.

kramer

Answer:

Isaac walked a distance of 5 blocks, and his displacement was 3 blocks north.

Explanation:

Distance is what he covered from the beginning, while displacement was what he covered in a specific direction

7 0

3 years ago

A block of mass 12.2 kg is sliding at an initial velocity of 6.65 m/s in the positive x-direction. The surface has a coefficient

valentina_108 [34]

Explanation:

Given that,

Mass of the block, m = 12.2 kg

Initial velocity of the block, u = 6.65 m/s

The coefficient of kinetic friction, $\mu_k=0.253$

(a)The force of kinetic friction is given by :

$f=\mu_k mg$

mg is the normal force

So,

$f=0.253\times 12.2\times 9.8\\\\f=30.24\ N$

(b) Net force acting on the block in the horizontal direction,

f = ma

a is the acceleration of the block

$a=\dfrac{f}{m}\\\\a=\dfrac{30.24}{12.2}\\\\a=2.47\ m/s^2$

(c) Let d is the distance covered by the block before coming to the rest. Using third equation of motion as follows :

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(6.65)^2}{2\times 2.47}\\\\d=-8.95\ m$

Hence, this is the required solution.

3 0

3 years ago

A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance It takes the pot 0.420 s to pa

eduard

Answer:

the distance of the top of the window below the windowsill from which the flowerpot fell is 0.31 m

Explanation:

given information:

time, t = 0.420 s

height, h = 1.9 m

the the vertical motion equation:

h = $v_{0}$ t + $\frac{1}{2} gt^{2}$

where

h = height (m)

$v_{0}$ = initial velocity (m/s)

t = time (s)

g = gravitational force (9.8 $m/s^{2}$ )

first we calculate the velocity of the flowers pot when it reaches top window

h = $v_{0}$ t + $\frac{1}{2} gt^{2}$

1.9 = $v_{0}$ (0.42) + ( $\frac{1}{2} 9.8 0.42^{2}$ )

$v_{0}$ = (1.9 - ( $\frac{1}{2} 9.8 0.42^{2}$ ))/0.42

= 2.47 m/s

now we can find the distance of the windowsil

$v^{2} =v_{0} ^{2}$ + 2gh

v = 0, thus

2gh = - $v_{0}^{2}$

h = - $v_{0}^{2}$ /2g

= $(- 2.47^{2} )$ / (2 x 9.8)

= 0.31 m

6 0

3 years ago

nika2105 [10]

Answer:

Explanation:

I hope this helps

5 0

3 years ago