If 7.79 mol of NO2 occupy 17.8 L, how many liters will 4.31 mol of NO2 occupy at the same temperature and pressure?
1 answer:
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The new volume : 21.85 ml
<h3>Further explanation</h3>Given
V1=25,0 ml
P1=725 mmHg
T1=298K is converted to
T2=273'K
P2=760 mmHg atm
Required
V2
Solution
Combined gas law :
Input the value :
V2=(P1.V1.T2)/(P2.T1)
V2=(725 x 25 ml x 273)/(760 x 298)
V2=21.85 ml
Answer:
The answer to your question is 92.7%
Explanation:
Balanced Chemical reaction
3 Zn + Fe₂(SO₄)₃ ⇒ 2Fe + 3ZnSO₄
Molecular weight
Zinc = 65.4 x 3 = 196.2g
Iron (III) = 56 x 2 = 112 g
Proportions
196.2 g of Zinc ------------------ 112 g of Iron
20.4 g of Zinc ----------------- x
x = (20.4 x 112) / 196.2
x = 2284.8/196.2
x = 11.65 g of Iron
% yield =
% yield = 0.927 x 100
% yield = 92.7
Mg+O2=MgO
24 g. = 40 g
3 g. = x
24 g. = 40 g
3 g. = x