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Sladkaya [172]
3 years ago
6

If you were to yell at a canyon wall, you would hear yourself a short time later. This is because sound can be

Physics
2 answers:
mojhsa [17]3 years ago
5 0
The answer is answer b refracted

Nadusha1986 [10]3 years ago
3 0
Reflected is the answer
hope this helps:)

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The speed of a 2.0-kg object changes from 30 m/s to 40 m/s during a 5.0-second time interval.
AnnyKZ [126]

Answer:

F = 2 * 30 / 5 = 12 N to stop forward motion

F = 2 * 40 / 5 = 16 N to accelerate to 90 degrees

(12^2 + 16^2)^1.2 = 20 N   average force applied

5 0
3 years ago
Suppose the ski patrol lowers a rescue sled carrying an injured skier, with a combined mass of 97.5 kg, down a 60.0-degree slope
Kitty [74]

a. 1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b.21,835 J work, in joules, is done by the rope on the sled this distance.

c. 23,170 J   the work, in joules done by the gravitational force on the sled d. The net work done on the sled, in joules is 43,670 J.

       

<h3>What is friction work?</h3>

The work done by friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement

a. How much work is done by friction as the sled moves 28m along the hill?

ans. We use the formula:

friction work = -µ.mg.dcosθ

  = -0.100 * 97.5 kg * 9.8 m/s² * 28 m * cos 60

= -1337.3 J

-1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b. How much work is done by the rope on the sled in this distance?

We use the formula:

Rope work = -m.g.d(sinθ - µcosθ)

rope work = - 97.5 kg * 9.8 m/s² * 28 m (sin 60 – 0.100 * cos 60)

                     = 26,754 (0.816)

                     = 21,835 J

21,835 J work, in joules, is done by the rope on the sled this distance.

c.  What is the work done by the gravitational force on the sled?

By using  the formula:

Gravity work = mgdsinθ

                    = 97.5 kg * 9.8 m/s² * 28 m * sin 60

                    = 23,170 J

23,170 J   the work, in joules done by the gravitational force on the sled .

       

D. What is the total work done?

By adding all the values

work done =  -1337.3 + 21,835 + 23,170

                 = 43,670 J

The net work done on the sled, in joules is 43,670 J.

Learn more about friction work here:

brainly.com/question/14619763

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4 0
2 years ago
What is one way to describe elements
Talja [164]

Answer:

They are the smallest pancise of any matere

4 0
3 years ago
What is the similarity between pushing and lifting? What is the difference?
MA_775_DIABLO [31]

Answer:

the similarity is that hands are applied and force

7 0
2 years ago
a small insect viewed through a convex lens is 2.5 cm from the lens and appears 2.5 times larger than its actual size. part a wh
Amiraneli [1.4K]

The lens' focal length is 1.5 cm, and its focal length is equal to half its radius of curvature, as shown by the formula f=R2 f = R 2, where f seems to be the focal length as well as R is indeed the radius of curvature.

<h3>What does focal length mean?</h3>

When a lens is focussed at infinity, the focal length of the lens is discovered. We can determine the angle of view, or the amount of the scene will be caught, and the magnification, or how big the individual elements will be, by measuring the focal length of the lens. A narrower field of view and a higher magnification result from a longer focal length.

<h3>How do focal length or wavelength work?</h3>

As wavelength and refractive index are inversely connected, the focal length of a lens varies inversely with each of them. The focal length of a lens varies directly with wavelength of light employed. The main reason chromatic aberration occurs is due to this. No relationship exists between the focal length and the frequency of a light.

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5 0
1 year ago
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