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Sladkaya [172]
3 years ago
6

If you were to yell at a canyon wall, you would hear yourself a short time later. This is because sound can be

Physics
2 answers:
mojhsa [17]3 years ago
5 0
The answer is answer b refracted

Nadusha1986 [10]3 years ago
3 0
Reflected is the answer
hope this helps:)

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A particular HeNe laser beam at 633 nm has a spot size of 0.8 mm. Assuming a
Kobotan [32]

Answer:

Explanation:

A

8 0
3 years ago
A thin rod of length 0.79 m and mass 130 g is suspended freely from one end. It is pulled to one side and then allowed to swing
-Dominant- [34]

Answer:

a) 0.3965 j

b) 0.3112 m

Explanation:

The picture attached explains it all. Thank you

3 0
3 years ago
A music fan at a swimming pool is listening to a radio on a diving platform. The radio is playing a constant- frequency tone whe
joja [24]

Answer:

The Doppler Effect is given by the following relation;

f' = \left (\dfrac{v + v_0}{v - v_s} \right) \times f

Where;

f' = The frequency the observer hears

f = Actual frequency of the wave

v = The velocity of the sound wave

v_o = The velocity of the observer

v_s = The velocity of the source

Where the observer is stationary, we have;

(i) When the source is moving in the direction of the observer

f' = \left (\dfrac{v }{v - v_s} \right) \times f

(ii) When the source is receding from the observer, we have;

f' = \left (\dfrac{v }{v + v_s} \right) \times f

Therefore;

(a) A person left behind on the platform

For a person left behind on the platform, we have that the radio source is receding, therefore, we have;

f' = \left (\dfrac{v }{v + v_s} \right) \times f

(1) Given that (v + v_s) > v, therefore, v < (v + v_s), f' < f, the frequency heard by the person left on the platform, f', is smaller (lower) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively smaller

(b) A person down below floating on a rubber raft

For the the person down below on the rubber raft, the radio source is advancing

Therefore, the radio source is moving towards the person at rest down on the rubber raft, therefore, we have;

f' = \left (\dfrac{v }{v - v_s} \right) \times f

(1) Given that (v - v_s) < v, therefore, f' > f, the frequency heard by the person down below floating on the rubber raft, f', is greater (higher) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively greater (higher)

Explanation:

7 0
3 years ago
An iron wire has length 8.0m and a diameter 0.50mm. The sir has a resistance R.
Rudik [331]
The re<span>sistance of the second wire is 16 R.
where R is the resistance of the first wire.

R = </span>ρ\frac{l}{A}
where l = length of the wire
A = area of the wire
A = \pi r^{2} where, r = \frac{diameter of wire}{2}

Thus, on finding the ratio of resistance of the two wires, we get,

\frac{R1}{R2} =  \frac{l1A2}{l2A1}

here, R1 = R
l1 = 8m
l2 = 2m
A1=π0.25^{2}
A1=π0.50^{2}

we get. R2 = 16R
7 0
3 years ago
two tugboats pull a disabled supertanker. each tug exerts a constant force of 2.20×106 n , one at an angle 19.0 ∘ west of north,
asambeis [7]

The amount of work the two tugboats completed on the supertanker W = 3.12 × 10^9 joules .

Work is a physics term used to describe the energy transfer that takes place when an object is moved over a distance by an external force, at least some . The component of the force acting along the path multiplied by the length of the path can be used to calculate work if the force is constant. Mathematically, this idea is expressed as W = fd, where W is the work and f is the force multiplied by d, the distance. Work is completed when the force is applied at an angle of with respect to the displacement. Performing work on a body involves moving it in its entirety from one location to another as well as other methods.  However, the work is thought to be negative if the applied force is in opposition to the item's motion, indicating that energy is being pulled away from the object

Learn more about work here:

brainly.com/question/1374468

#SPJ4

7 0
1 year ago
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