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ira [324]
2 years ago
12

A compass originally points North; at this location the horizontal component of the Earth's magnetic field has a magnitude of 2e

-5 T. A bar magnet is aligned East-West, pointing at the center of the compass. When the center of the magnet is 0.25 m from the center of the compass, the compass deflects 70 degrees. What is the magnetic dipole moment of the bar magnet?
Physics
1 answer:
astraxan [27]2 years ago
8 0

Answer:

μ =5.40 A-m²

Explanation:

The components of the net magnetic field are the magnetic field of the dipole and the magnetic field of Earth, then from the right triangle, the deflection angle is computed by

tan θ = Bdipole / Bearth     ⇒   Bdipole = Bearth* tan θ  

Bdipole = 2e-5 T*tan 70° = 5.49e-5 T

The magnetic field at the location of the compass due to the dipole has a magnitude

Bdipole = (μ₀/4π)(2μ/r³)    ⇒    μ = Bdipole r³ / 2(μ₀/4π)

μ = (5.49e-5 T)(0.27m)³ / 2(1 × 10−7 T m² /(C m/s)) = 5.40 A-m²

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The acceleration of the object at time t = 0.7 s is most nearly equal to which of the following?
VladimirAG [237]

We have that for the Question "the acceleration of the object at time t = 0.7 s is most nearly equal to which of the following?"

  • it can be said that the acceleration of the object at time t = 0.7 s is most nearly equal to the slope of the line connecting the origin and the point where the graph where the graph crosses the 0.7s grid line

From the question we are told

the acceleration of the object at time t = 0.7 s is most nearly equal to which of the following?

Generally the equation for the Force  is mathematically given as

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For more information on this visit

brainly.com/question/23379286

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