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kenny6666 [7]
3 years ago
14

An Electric Field does 25 mJ of work to move a +7.4 μC charge from one point to another. What is the potential difference betwee

n these two points?
Physics
1 answer:
son4ous [18]3 years ago
7 0

Answer:

P.d = 3.4 * 10^3 volts

Explanation:

Given the following data:

Workdone = 25mJ = 25*10^{6} Joules

Charge = 7.4 μC = 7.4 * 10^{3} C

To find the potential difference;

P.d = workdone/charge

Substituting into the equation, we have;

P.d = 25 * 10^6/7.4*10^3

P.d = 3.4 * 10^3 volts

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If the moon moved closer to the earth, how would the gravitational force between them change?.
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2 years ago
A 10-cm-thick aluminum plate (α = 97.1 × 10−6 m2/s) is being heated in liquid with temperature of 475°C. The aluminum plate has
Anuta_ua [19.1K]

Answer:

T_0 = 338.916 Degree\ celcius

Explanation:

Given data:

Thickness of aluminium sheet 10 cm

initial temperature = 25 degree celcius

Assumption

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from the information given in the question we have

T_S ≈T_∞ , it implies we have h → ∞

from table 4.2 Biot number → ∞ the value of

\lambda_1 = 1.5708 and A_1= 1.2732

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Temperature at center after 15 second of heating

\theta _{0 wall} = \frac{T_0 - T_{\infity}}{T_i -T_{\infity}} = A_i e^{\lambda_1^2 t}

T_0 = T_i -T_{\infity} \times A_i e^{\lambda_1^2 t}

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T_0 = 338.916 Degree\ celcius

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