Question

An Electric Field does 25 mJ of work to move a +7.4 μC charge from one point to another. What is the potential difference between these two points?

Answer 1

Answer:

P.d = 3.4 * 10^3 volts

Explanation:

Given the following data:

Workdone = 25mJ = 25*10^{6} Joules

Charge = 7.4 μC = 7.4 * 10^{3} C

To find the potential difference;

P.d = workdone/charge

Substituting into the equation, we have;

P.d = 25 * 10^6/7.4*10^3

P.d = 3.4 * 10^3 volts